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balu736 [363]
3 years ago
5

I’m now sure how to work this out... my teacher had shown us this today at the end of class.

Mathematics
1 answer:
Kipish [7]3 years ago
4 0
That's "5 to the negative seventh power," and is equal to

      1            1
---------- = --------- .  I would accept "1/(5^7)" as correct.
    5^7       78125
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A group of fitness club members lose a combined total of 28 kg in one week there approximately 2.2 pounds and 1 kg assuming the
Akimi4 [234]

Answer:

  8.8 pounds

Step-by-step explanation:

There are 7 days in a week, so the daily loss was ...

  (28 kg)/(7 days) = 4 kg/day

In pounds, that is about ...

  (4 kg/day)(2.2 lb/kg) = 8.8 lb/day

6 0
3 years ago
If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav
allsm [11]

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q =  Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

q+d=11

q=11-d

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

25q+10d=200

Substitute the value of q in above equation.

25(11-d)+10d=200

275-25d+10d=200

15d=75  

d=5  

Substitute the value of d in q=11-d

q=11-5

q=6

Hence, Trent has 6 quarters and 5 dimes.

4 0
3 years ago
Please help !!!!!!!!!
Ainat [17]

Answer:

5

Step-by-step explanation:

3x -12 = -36

-36 ÷ -3 = 12

-7 + 12 = 5

7 0
2 years ago
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Suppose the average farm owned by the farmers who joined Shays' Rebellion had an area of
zloy xaker [14]

Answer:

d would be the answer

Step-by-step explanation:

i took the test

8 0
2 years ago
A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

9514 1404 393

Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

__

The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
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