Answer:
WE reject the Null and conclude that one of the drug is more effective than the other.
Step-by-step explanation:
Given :
Diet 1 3.4 10.9 2.8 7.8 0.9 5.2 2.5 10.5 7.1 7.5
Diet 2 11.9 13.1 11.6 6.8 6.8 8.8 12.5 8.6 17.5 10.3
This is a matched pair sample :
The hypothesis :
H0 : μd = 0
H1 : μd ≠ 0
Hence, we intun the difference between the two groups of value :
Difference, d = -8.9,-2.2,-8.8,1,-5.9,-3.6,-10,1.9,-10.4,-2.8
The test statistic :
dbar ÷ (Sd/√n)
dbar = mean of difference = Σd / n = - 49.7 / 10 = - 4.97
Standard deviation of difference, Sd = 4.51
Test statistic :
-4.97 ÷ (4.51/√10)
Test statistic = - 3.485
The sample size, n = 10
df = n - 1 ; 10 - 1 = 9
Critical value (0.10, 9) = 1.833
If Test statistic > |Critical value |
Since 3.486 > 1.833 ; WE reject the Null and conclude that one of the drug is more effective than the other
