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storchak [24]
3 years ago
12

13. y = -x2 + 12x - 5 Axis of symmetry (aos):

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

Slope = 24.000/2.000 = 12.000

When y = 0 the value of x is 5/-12 the line therefore crosses the x axis at x=-0.41667

x-intercept = 5/-12  = -0.41667

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st
Naily [24]

Answer:

\boxed{2^{\frac{802}{27}} \cdot 3^9}

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

\text{Use } \LaTeX !

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

\left(\dfrac{1}{3^2}  \cdot \dfrac{1}{4^5}  \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3

Also,

\boxed{a^{0} = 1, a\neq 0 }

\left(\dfrac{1}{9}  \cdot \dfrac{1}{1024}  \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

Note

\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq  0}

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

Note

\boxed{\dfrac{1}{\dfrac{1}{a} }  = a}

9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)

Once

9216=2^{10}\cdot 3^2 \implies  9216^3=2^{30}\cdot 3^6

\boxed{(a \cdot b)^n=a^n \cdot b^n}

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27} $

We have

\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)

Also, once

\boxed{\dfrac{c^a}{c^b}=c^{a-b}}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27

As

30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27}  =\dfrac{802}{27}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3

2^{\frac{802}{27}} \cdot 3^9

4 0
3 years ago
A bag contains 4 white, 2 blue, and
7nadin3 [17]

Answer:

1/2 for red

2/3

b+w=1/2

r+w=5/6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use the compound interest formula A =​P(1 + ​r) t and the given information to solve for r.
Dmitry [639]

Answer:

Rounding to nearest hundredths gives us r=0.06.

So r is about 6%.

Step-by-step explanation:

So we are given:

A=P(1+r)^t

where

A=2300

P=1600

t=6.

A=P(1+r)^t

2300=1600(1+r)^6

Divide both sides by 1600:

\frac{2300}{1600}=(1+r)^6

Simplify:

\frac{23}{16}=(1+r)^6

Take the 6th root of both sides:

\sqrt[6]{\frac{23}{16}}=1+r

Subtract 1 on both sides:

\sqrt[6]{\frac{23}{16}}-1=r

So the exact solution is r=\sqrt[6]{\frac{23}{16}}-1

Most likely we are asked to round to a certain place value.

I'm going to put my value for r into my calculator.

r=0.062350864

Rounding to nearest hundredths gives us r=0.06.

8 0
3 years ago
A) a shopkeeper buys a camera for $300 and sells it at $360. Calculate the percentage profit.
Lilit [14]
A) profit/original price x100 =percentage profit

(Profit: 360-300=$60)

=60/300 x100
=20%

b) two cameras (original price): 300x2= $600
two cameras (price sold): 360x2 = $720

Profit without discount: 720-600= $120

120-100= $20 discount

20/720 x100 =2.78%
4 0
2 years ago
Read 2 more answers
What does magnitude mean in this question???
zhannawk [14.2K]
Magnitude - 1. The great size or extent of something; great importance. 2. Size. 3. The degree of brightness of a star.

- via Google

It more than likely means size.
5 0
3 years ago
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