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Zepler [3.9K]
2 years ago
14

Solve for y thank you

Mathematics
1 answer:
Semenov [28]2 years ago
4 0

Answer: y = 1

Step-by-step explanation:

9x + (3 x 1) = 12

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Which equation is equivalent to x + 8 = 21?
soldi70 [24.7K]

Answer:

b

13+8=21

21×4=84

84÷4=21

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2 years ago
Evaluate lim θ→0 sin(cos 8θ)/sec 5θ.
kenny6666 [7]
In this case, we are given with the expression <span>sin(cos 8θ)/sec 5θ and is asked to evaluate the expression with limit as theta approaches 0. In this case, we just substitute 0 to theta. cos 0 is equal to 1 hence sec 0 is also equal to 1. sin theta is equal to 0.0175. Answer os 0.0175.</span>
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2 years ago
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A triangle has 34 degree angle and a 102 degree angle what is the third angle
coldgirl [10]

Answer: 44 degrees.

Step-by-step explanation: Since the sum of the measures of the angles in a triangle add up to 180 degrees, we can figure out the measure of the third angle by adding the first two angles and subtracting the sum from 180. 102 + 34 = 136. 180 - 136 = 44, so the measure of the third angle is 44 degrees.

8 0
2 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
3 years ago
In 2009, the American Time Use Survey found that the average American spends 2.8 hours a day watching TV. Suppose the standard d
Anit [1.1K]

Answer:

4.72 hours/day

Step-by-step explanation:

Mean time spent watching TV (μ) = 2.8 hours a day  

Standard deviation (σ) = 1.5 hours a day

The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:

z=\frac{X-\mu}{\sigma} \\1.282=\frac{X-2.8}{1.5}\\ X=4.72\ hours/day  

On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.

8 0
3 years ago
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