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Stels [109]
3 years ago
12

Climbing ar an indoor rock-climbing gym costs $8 per hour. Lizbeth has a $30 gift card to spend at the gym. Write an algebraic e

xpression for the dollar amlunt Lizbeth will have left on the card after she spends h hours of climbing. Can Lizbeth climb for 4.5 hours using only her card? explain how you know
Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

30=8x

Step-by-step explanation:

lizabeth cant climb for 4.5 hrs because if you divide 30 by 8 you get 3.75. so Lizabeth can climb for 3.75 hrs using only her $30 gift card

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What is the solution to −6 − (−2)?
fomenos
- 6 - (-2)

- (-2) = 2 
* two negatives = one positive

-6 + 2 = -4

-4 is your answer

hope this helps
7 0
2 years ago
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18 necklaces made in 3 hours. so how many are made in 3 hours?
Westkost [7]

Answer: there are 18 necklaces made in 3 hours

Step-by-step explanation:

6 0
2 years ago
Calculate the largest rectangular area one can enclose with 14 inches of string?
bagirrra123 [75]

The correct answer to this question is <span>12.25 sq inches.
</span>

The largest rectangle is a square.

So if you divide 14" by 4 then you get 4 3.5" sides.


Area of a rectangle = L*W

<span>Area of a rectangle = 3.5 * 3.5</span>

<span>Area of a rectagle = 12.25 sq inches</span>


3 0
2 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0
3 years ago
A raffle prize of 14x^2/15dollars is to be divided among 7x people. Write an expression for the amount of money that each person
vladimir2022 [97]

For this case we must divide the following expression:

\frac {\frac {14x ^ 2} {15}} {7x}

And in this way we get the amount of money that each person will receive.

Then applying double C we have:

\frac {14x ^ 2} {15 * 7x} =\\\frac {14x ^ 2} {105x} =\\0.133x

Thus, each person has 0.133x of money!

Answer:

0.133x

7 0
3 years ago
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