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yarga [219]
2 years ago
6

PLEASE HELP MATH QUESTION

Mathematics
1 answer:
Sholpan [36]2 years ago
8 0

Answer:

c is the answer

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FIND AREA OF SHADED SEGMENT. WILL GIVE BRAINLIEST FOR CORRECT ANSWER
Xelga [282]
By geometry,
area \: of \: shaded \: region \:  =  (\: area \: of  \: square \:  -  \: 2 \times (area \: of \: semi - circles)) \div 2
=  ({l}^{2}  - 2 \times \pi  \times {r}^{2} ) \div 2
l = 6 \\ r = l \div 2 = 3
= (36 - \pi \times  {3}^{2} ) \div 2
= 3.86
area of shaded region = 3.9
3 0
2 years ago
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Which point is on the perpendicular bisector of the segment with endpoints (-2,5) and (-2,-3)
Kryger [21]
(-2,0)

Lies on the X axis makes it perpendicular with the other points
3 0
2 years ago
Please help me guys!!!
sdas [7]
I can't see the whole problem
3 0
3 years ago
SOMEONE PLEASE HELP ME
goldfiish [28.3K]

Answer:

First break up 72 into

36 x 2 x -1

Then take the square root of 36

6 square root 2 x -1

Finally make square root -1 = i

6i square root 2 is your answer

Step-by-step explanation:

7 0
3 years ago
Can someone please help fast will give brainelist
Vanyuwa [196]

Answer:

A.

Step-by-step explanation:

y = mx + c

m = y - y¹ / x - x¹

= 4-3 / 4-2

= 1/2

using (4,4)

4 = 1/2 × 4 + c

4 = 2 + c

c = 2

equ..=

y = 1/2x + c

7 0
3 years ago
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