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yarga [219]
3 years ago
6

PLEASE HELP MATH QUESTION

Mathematics
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

c is the answer

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Describe and correct the error a student made in finding the midpoint of CD with ​C(​4,5) and ​D(​1,​4).
Andru [333]

Using the given information, the midpoint of CD is (2.5, 4.5)

<h3>Midpoint of a line </h3>

From the question, we are to determine the midpoint of line CD

The midpoint of a line is given by the formula,

[(x₁ + x₂)/2 , (y₁ + y₂)/2]

From the given information, we are to find the midpoint of line CD with coordinates C(​4,5) and ​D(​1,​4)

∴ x₁ = 4

x₂ = 1

y₁ = 5

y₂ = 4

Putting the parameters into the formula for midpoint, we get

[(x₁ + x₂)/2 , (y₁ + y₂)/2]

[(4 + 1)/2 , (5 + 4)/2]

(5/2 , 9/2)

(2.5, 4.5)

Hence, the midpoint of CD is (2.5, 4.5)

Learn more on Midpoint of a line here: brainly.com/question/896396

#SPJ1

6 0
2 years ago
PLEASE HELP
irina [24]

Answer:

12\sqrt{3} feet

Step-by-step explanation:

In a 30-60-90 triangle, the ratios of the side lengths of the triangle is 1:\sqrt{3} :2

Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.

First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

\frac{x}{3} * \sqrt{3} = \frac{\sqrt{3} x}{3} = 12

Solving for x, we find that

x=\frac{36}{\sqrt{3} } = \frac{36 * \sqrt{3} }{\sqrt{3} * \sqrt{3} } = \frac{36  \sqrt{3} }{3} = 12\sqrt{3}

So the length of the original pole would be 12\sqrt{3} feet

If you found this answer helpful, please consider marking it as brainliest, or give it a thanks and a 5 star review. Thanks!

6 0
3 years ago
a contractor needs to purchase 500 bricks. the dimensions of each brick are 5.1 cm by 10.2 by 20.3 cm, and the density of each b
AveGali [126]
No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.
5 0
4 years ago
Is 12.54 greater than 12.539?
Damm [24]

Answer:

yes

Step-by-step explanation:

12.54

>

12.53

reason why is because of the 4>5

8 0
3 years ago
Read 2 more answers
5000 is 1/10 of what
VikaD [51]
50,000 is the answer because if you multiply 5,000 and 10 you get 50,000. And if you divide 50,000 by 10 you get 5,000. Which is 1/10 of 50,000.
6 0
3 years ago
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