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Andre45 [30]
4 years ago
11

(5.9 - 5.3) x 7.2 + (1.4)²

Mathematics
2 answers:
den301095 [7]4 years ago
7 0

Solve using the order of operations: parentheses, exponents, multiplication/division, addition/subtraction)

(5.9-5.3)(7.2)+1.4^2

0.6(7.2) + 1.4^2

0.6(7.2) + 1.96

4.32+1.96

6.28

vichka [17]4 years ago
5 0

PEMDAS definitely 6.28

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A hotel off two activity packages.one costs $192 and includes 3h of horseback riding and 2h of parasailing. The second costs $21
Pie
H = cost of horseback riding per hr, p = cost of parasailing per hr
3h + 2p = 192...multiply by 2
2h + 3p = 213..multiply by -3
------------------
6h + 4p = 384 (result of multiplying by 2)
-6h - 9p = - 639 (result of multiplying by -3)
-----------------add
-5p = - 255
p = -255/-5
p = 51 <== cost of 1 hr for parasailing

3h + 2p = 192
3h + 2(51) = 192
3h + 102 = 192
3h = 192 - 102
3h = 90
h = 90/3
h = 30 <== cost of 1 hr of horseback riding
6 0
3 years ago
The number of unbroken charcoal briquets in a 20-pound bag filled at the factory follows a normal distribution with a mean of 45
sesenic [268]
The interval of filled bags is at confidence interval of 95%.

At 95% confidence interval, Z=1.96 (from Z tables).

But,
Z= (x-mean)/sd => 1.96 = (x-450)/20 => x (upper limit)= 20*1.96+450489 bags

Lower limit or minimum number bags to avoid replace= 450-1.96*20 =411 bags
5 0
3 years ago
Read 2 more answers
A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air​ resistance, its heigh
lara [203]
This problem involves the use of a kinematic equation since it involves the motion of an object. The equation for the height of the object is given as:

s = -<span>16*t^2+v_o*t

Also, the initial velocity, v_o, was also said to be equal to 128 ft/s.

For the first question, </span><span>the​ time(s) that the projectile will reach a height of 240 ft when v_o is 128 feet per second, can be solved using the given equation and the quadratic formula. The resulting quadratic equation is then </span>-16*t^2 + 128*t -240 =0, where a =16, b =128, and c =-240. The quadratic formula is equal to [-b <span>± sqrt(b^2 -4ac)]/2a. This gives two answers t = 3 seconds and t = 5 seconds. This might be because the projectile has a parabolic path, thus, it reaches the height of 240 ft, before and after it reaches a peak.

For the second question, the time it takes for the projectile to reach the ground is obtained by setting the distance, s, equal to zero. In this case, t = 8 seconds.</span>
5 0
3 years ago
Use the slope of the given line to construct a parallel line
Troyanec [42]

Answer:

y = - \frac{4}{3} x - 7

Step-by-step explanation:

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m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (3, - 2) ← 2 points on the line

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To find c substitute P(- 3, - 3) into the partial equation

- 3 = 4 + c ⇒ c = - 3 - 4 = - 7

y = - \frac{4}{3} x - 7 ← equation of parallel line

6 0
3 years ago
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Help!! 10 pts and brainliest!
o-na [289]

Answer:

6

Step-by-step explanation:

scale factor is 0.25

so

∴ x = 1.5 ÷ 0.25 = 6

5 0
3 years ago
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