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3 years ago

The graph below shows the number of paintballs a machine launches, y, in x seconds:

Mathematics

2 answers:

IrinaVladis [17]3 years ago

5 0

Answer:

The expression that can be used to calculate the rate per second at which the machine launches the balls is fraction 20 over 4.

Step-by-step explanation:

The x-axis label is Time in seconds, and the x-axis values are from 0 to 20 in increments of 4 for each grid line.

And the y-axis label is Number of Balls and the y-axis values from 0 to 100 in increments of 20 for each grid line.

If the ordered pairs (4,20) and (8,40) are on the graph, then the slope of the line will be represented by

$M = \frac{40 - 20}{8 - 4} = \frac{20}{4}$

Therefore, the expression that can be used to calculate the rate per second at which the machine launches the balls is fraction 20 over 4. (Answer)

Readme [11.4K]3 years ago

3 0

Answer:

20/4

Step-by-step explanation:

if you look at the chart it is clearly showing that every 4 seconds it is shooting out 4 balls.

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Grant has 2 over 3 cup of ice cream in a bowl. He then removes two 1 over 6 cups of ice cream to share with his little brother.

Volgvan

It would be the second answer. He starts with 2/3 cup, then take out 2 1/6 cup amounts, which make 2/6 cup. Since he's taking it out, you would subtract it from the original value. So you would get 2/3 cup minus 2/6 cup and to make the denominators equal you would multiply 2/3 cup by 2, so you would have 4/6 cup minus 2/6 cup which equals 2/6 cup.

6 0

4 years ago

Read 2 more answers

A candle is lit and the length of the burning candle changes at a constant rate of -1.6 inches per hour. 3 hours after the candl

Gnesinka [82]

Answer: The length of the candle was 13.5 inches before it was lit.

Step-by-step explanation:

Let the length of candle in the beginning be c.

Constant rate of change in length of candle= -1.6 inches per hour

Since rate of change is constant so the length of candle can be represented by a linear function [Linear function has constant rate of change.]

Linear function : f(x)= mx+c , where x= independent variable.

m= constant rate of change and c= initial value of function.

Let x = Number of hours after the candle was lit.

Put m= -1.6 , x= 3 and f(x)= 8.7 , we get

$8.7=-1.6(3)+c\\\\ 8.7= -4.8+c\\\\ c=8.7+4.8=13.5$

Hence, the length of the candle was 13.5 inches before it was lit.

5 0

4 years ago

Write an equation of the line that passes through (0, 3) and (−5, 2.5)

julia-pushkina [17]

Answer:

y=.1x+3 I think that is the answer

6 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through the

Lana71 [14]

Answer:

The slope of the line that passes through the points is 0 slope. That is B is the answer.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20

ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

$\sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}$

$\sf a^{-m}=\dfrac{1}{a^m}$

First convert radical form to exponent form and then apply exponent law.

$\sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}$

$\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}$

$= \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}$

3 0

2 years ago