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Law Incorporation [45]
3 years ago
5

An airliner passes over an airport at noon traveling 520 mi/hr due west. At 1:00 p.m., another airliner passes over the same air

port at the same elevation traveling due south at 550 mi/hr. Assuming both airliners maintain their (equal) elevations, how fast is the distance between them changing at 3:00 p.m.?​
Mathematics
1 answer:
julsineya [31]3 years ago
5 0
Well let’s see I tried to think and I couldn’t come up But I’ll tell U when I know
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The population of bats in a large cave is 7000 and is growing exponentially at 14% per year. Write a function to represent the p
Evgen [1.6K]

Answer:

y=7000+14^t

Step-by-step explanation:

This equation shows that the original population of bats was 7000 and grows exponentially at a rate of 14% per year.

I put the graph below so you can see it.

4 0
3 years ago
Mario was visiting the carnival when he noticed a few number relationships.
Alik [6]
There would be 30 adults because, if you were to take 3/10 and multiple both numbers until the denominator was 100 (10 X 10 = 100, 10 X 3 = 30). Resulting in your numerator to be 30. Therefore there were 30 adults.
5 0
4 years ago
Solve for x 10x+1=12x-5
Verdich [7]

Answer:

x=3

Step-by-step explanation:

1) 10x+1-1 = 12x-5-1, this becomes a new equation

Equation: 10x = 12x-6

2) 10x-12x = 12x-12x-6, this become a new equation

Equation: -2x = -6

3) Divide both sides by -2: -2x/2 = -6/2

4) Once you simplify, you will get x=3

Hope this helps!

6 0
3 years ago
Hi can someone help me please
tensa zangetsu [6.8K]

Answer: yes

Step-by-step explanation:

3 0
3 years ago
I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
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