Given:
Area(A)= 63m^2
Length (L)= 2W+5
Width (W)=?
A=LxW
63=(2W+5)(W)
63=2W^2 + 5W
0=2W^2+5W-63
0=(2W-9)(W+7)
2W-9=0 then W=4.5 and W+7=0 then W=-7
Can only use 4.5 since it is positive and distance is positive.
W= 4.5 m
L=2W+5=2 (4.5)+5=9+5=14m
B.) 20
If x goes from 2 to 4 it was multiplied by 2. you would do the same to the y. 10*2=20
1/4 acre x 100 acres = 25 acres
208.71" = one side of 1 acre squared in feet
2 x 1/4 x 208.17" = 104.355" (2 x 1/4 acre long ends in feet)
200 x 208.71" = 41,742.000" (2 x 100 (acre long sides) x 208.71")
41,846.335" divided by 3 = 13,948.785 yards of fencing required
Answer:
No solution
Step-by-step explanation:
These are parallel lines, which never meet. Therefore, there is no solution.
