counterclockwise 90 degrees
Ok soo
-5x+x/2=9
- 4x/2=9
-(2^2-1 *x)=9
2x/2=- 9/2
x=- 9/2
x= -4 1/2
The known endpoint is P = (-16,0)
Let Q = (x,y) be the other endpoint. It is unknown for now.
Looking at the x coordinates of P and Q, we see that they are -16 and x respectively. Adding these values up gives -16+x. Dividing that result by 2 gives (-16+x)/2. This result is exactly equal to the midpoint x coordinate, which is the x coordinate of M (0).
So we have this equation (-16+x)/2 = 0. Let's solve for x
(-16+x)/2 = 0
2*(-16+x)/2 = 2*0
-16+x = 0
x-16 = 0
x-16+16 = 0+16
x = 16
Therefore the x coordinate of point Q is 16.
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Let's do something similar for the y coordinates.
The y coordinates of P and Q are 0 and y respectively. Add them up and divided by 2, then set the result equal to -16 (y coordinate of midpoint M) getting this equation (0+y)/2 = -16
Solve for y
(0+y)/2 = -16
y/2 = -16
2*y/2 = 2*(-16)
y = -32
The y coordinate of point Q is -32
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The point Q goes from (x,y) to (16, -32)
Final Answer: (16, -32)
If we observe the graph it crosses x-axis at the following points:
1) x = - 2
2) x = - 5
This means, x+ 2 and x + 5 are the factors of the polynomial. A polynomial can be expressed as the product of its factors. So we can express the given polynomial as (x + 2)(x + 5)
Thus the answer to above question is option C
Answer:
x=5, y=6. (5, 6).
Step-by-step explanation:
-6x+6y=6
-6x+3y=-12
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simplify -6x+6y=6 into -x+y=1 and y=1-(-x)=1+x
-6x+3(1+x)=-12
-6x+3+3x=-12
-3x=-12-3
-3x=-15
3x=15
x=15/3
x=5
-6(5)+6y=6
-30+6y=6
6y=6-(-30)
6y=6+30
6y=36
y=36/6
y=6
