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Masteriza [31]
3 years ago
14

A soft drink machine outputs a mean of 24 ounces per cup. The machine's output is normally distributed with a standard deviation

of 3 ounces. What is the probability of filling a cup between 21 and 28 ounces? Round your answer to four decimal places.
Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

P(21

And we can find the probability with this difference

P(-1

And using the normal standard distribution or excel we got:

P(-1

Step-by-step explanation:

Let X the random variable that represent the soft drink machine outputs of a population, and for this case we know the distribution for X is given by:

X \sim N(24,3)  

Where \mu=24 and \sigma=3

We want to find this probability:

P(21

The z score is given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(21

And we can find the probability with this difference

P(-1

And using the normal standard distribution or excel we got:

P(-1

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kenny6666 [7]

Answer: (C) the number of groups

Step-by-step explanation: It cannot be the total because the total is 18, the size of the groups does not make sense because it seems that you are trying to find a total, and the difference makes no sense because this does not seem like a subtraction problem. (C) the number of groups makes sense because their is a total number of groups.

Hope this helps! :)

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3 years ago
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1.which side of AFED does AB in AABC correspond to?
erma4kov [3.2K]

Rotate one of them so the right angle is in the same orientation as the other one.

1. AB = DE

2. CB = FE

3. AC = DF

4. Compare the length of two known sides: cb and EF

CB = 3 and EF = 8

8/3 = 2 2/3 scale factor

5. Ab is side de. Multiply the length of ab by the scale factor:

4 x 2 2/3 = 10 2/3

6. FD = sqrt ( 10 2/3^2 + 8^2)

FD = 13 1/3

6 0
3 years ago
In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

3 0
3 years ago
When someone donated 14 gallons of paint to Rosendale Elementary School, the fifth grade decided to use it to paint murals. They
Naddika [18.5K]

Answer:

Answered

Step-by-step explanation:

Total amount of paint = 14 gallons

the paint was distributed equally among 4 classes

a. therefore each class would get \frac{14}{4} gallons of paint

= 3\frac{1}{2} gallons each

b.Three classes will use 3× paint of each class

= 3\times3\frac{1}{2}= 10(1/2) gallons

c. 4 student paint 30 square-foot wall the each student would paint

\frac{30}{4} = 7(1/2) square-foot wall.

d. each student will paint \frac{1}{4} of the wall since there are 4 students.

6 0
3 years ago
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
3 years ago
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