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Masteriza [31]
3 years ago
14

A soft drink machine outputs a mean of 24 ounces per cup. The machine's output is normally distributed with a standard deviation

of 3 ounces. What is the probability of filling a cup between 21 and 28 ounces? Round your answer to four decimal places.
Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

P(21

And we can find the probability with this difference

P(-1

And using the normal standard distribution or excel we got:

P(-1

Step-by-step explanation:

Let X the random variable that represent the soft drink machine outputs of a population, and for this case we know the distribution for X is given by:

X \sim N(24,3)  

Where \mu=24 and \sigma=3

We want to find this probability:

P(21

The z score is given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(21

And we can find the probability with this difference

P(-1

And using the normal standard distribution or excel we got:

P(-1

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 <span>P(at least 1 ) = 1 - P(exactly none) = 1 - (4/5)^6 = .738
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3 years ago
X + y = 30<br><br> 2x + 4y = 84<br><br> Substitution<br> or<br> Elimination<br> I
miv72 [106K]

Answer:

(X,Y)(18,12)

Step-by-step explanation:

x + y = 30

2x + 4y = 84

___________

2x+2y=60

2x+4y=84

_________

-2y=-24/-2y

y=12

2x+4(12)=84

2x+48=84

2x=84-48

2x/2=36/2

X=18

3 0
3 years ago
A plane rises from take off and flies at an angle 11° with the horizontal runway. When it has gained 750 feet find the distance
kogti [31]

Answer:

D=3930.632298 \approx 3930.6miles

Step-by-step explanation:

From the question we are told that

Angle  \theta=11\textdegree

Height of plane h  =750feet

Generally the equation for the total distance flown is mathematically given by

D=\frac{h}{sin\theta}

D=\frac{750}{sin11}

Therefore total distance flown is

D=3930.632298 \approx 3930.6miles

7 0
3 years ago
What is the value of the exponential expression below? 36^1/2
Dmitry [639]

Answer:

6

Step-by-step explanation:

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7 0
3 years ago
Solve the above que no. 55
aleksandr82 [10.1K]

Answer:

Let \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right), we proceed to prove the trigonometric expression by trigonometric identity:

1) \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right) Given

2) \left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)   \tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}

3) \left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)    

4) \left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)    \sin^{2}A+\cos^{2}A = 1

5) \frac{1}{\sin^{2}A\cdot \cos^{2}A}

6) \frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}    \sin^{2}A+\cos^{2}A = 1

7) \frac{1}{\sin^{2}A-\sin^{4}A} Result

Step-by-step explanation:

Let \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right), we proceed to prove the trigonometric expression by trigonometric identity:

1) \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right) Given

2) \left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)   \tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}

3) \left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)    

4) \left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)    \sin^{2}A+\cos^{2}A = 1

5) \frac{1}{\sin^{2}A\cdot \cos^{2}A}

6) \frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}    \sin^{2}A+\cos^{2}A = 1

7) \frac{1}{\sin^{2}A-\sin^{4}A} Result

4 0
3 years ago
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