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drek231 [11]
3 years ago
13

What is the greatest common factor of 30 and 72 ?

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0
I believe the answer is 6. I hope this helps love! :)
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BRAINLIST AND 40 POINTS PLEASE HELP ASAP NO ONE IS HELPING:(
stepladder [879]

Answer:

for #1 its B : output = input x5

and for #2 its C : output= input x2 +5

3 0
3 years ago
Estimate the height of a tree using the following measurements:height of the rod:180 cm,length of the shadow of the rod is 116 c
andriy [413]

Answer:

1303.45 cm

Step-by-step explanation:

The triangles formed by a rod and its shadow and a tree and its shadow are similar triangles, so the ratios of their heights to the lengths of their shadows are equal.

Let x be the height of the tree. Setting the ratios equal, we get:

180/116 = x/840

Solve for x:

x = 840 * (180/116)

x ≈ 1303.45 cm

6 0
3 years ago
Hurry Please!
blagie [28]
I believe the answer should be 4 and 2
3 0
3 years ago
Urgent help please! Answer any of the questions!
kiruha [24]

#1. x =    - (2y) / (1-y)

#2. x =    (-4y-3)/(1-y)

I can't really see the other questions, so I only did the first two. Hope this helps!


8 0
3 years ago
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The
sattari [20]

Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 \sqrt{\frac{0.8*0.2}{200} }

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

8 0
3 years ago
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