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Fudgin [204]
3 years ago
10

Which is equivalent to 4 square root of 9 1/2x?

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0

Answer:

B. 9 ^ 1/8x

Step-by-step explanation:

just did it and got it right

EastWind [94]3 years ago
6 0

Answer: 6\sqrt{2x}


Step-by-step explanation:

1. You have the following expression given in the problem above:

4\sqrt{\frac{9x}{2} }

2. Remove the perfects squares from the square root:

9=3^{2}

Then:

4*3\sqrt{\frac{x}{2}}=12\sqrt{\frac{x}{2}}

3. Now, rationalize the denominator, because it cotains an square root. Multiply the numerator and the denominator by \sqrt{2} and simplify, as following:

12\sqrt{\frac{x}{2}}=\frac{12(\sqrt{x})(\sqrt{2})}{(\sqrt{2})(\sqrt{2})}=\frac{12\sqrt{2x}}{(\sqrt{2})^{2}}=\frac{12\sqrt{2x}}{2}=6\sqrt{2x}


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-1 / 13

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(x 1,y1)  = (-10,5)

(x2, y2) = (3,4)

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What is the closed linear form of the sequence of the negative even integers starting with -2?
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The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as t
skad [1K]

Answer:

a) 0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

b) 0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

c) 0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

d) None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100.

This means that \mu = 273, \sigma = 100

A) What is the probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean?

Sample of 30 means that n = 30, s = \frac{100}{\sqrt{30}}

The probability is the p-value of Z when X = 273 + 16 = 289 subtracted by the p-value of Z when X = 273 - 16 = 257. So

X = 289

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{289 - 273}{\frac{100}{\sqrt{30}}}

Z = 0.88

Z = 0.88 has a p-value of 0.8106

X = 257

Z = \frac{X - \mu}{s}

Z = \frac{257 - 273}{\frac{100}{\sqrt{30}}}

Z = -0.88

Z = -0.88 has a p-value of 0.1894

0.8106 - 0.1894 = 0.6212

0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

B) What is the probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean?

Sample of 30 means that n = 50, s = \frac{100}{\sqrt{50}}

X = 289

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{289 - 273}{\frac{100}{\sqrt{50}}}

Z = 1.13

Z = 1.13 has a p-value of 0.8708

X = 257

Z = \frac{X - \mu}{s}

Z = \frac{257 - 273}{\frac{100}{\sqrt{50}}}

Z = -1.13

Z = -1.13 has a p-value of 0.1292

0.8708 - 0.1292 = 0.7416

0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

C) What is the probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean?

Sample of 30 means that n = 100, s = \frac{100}{\sqrt{100}}

X = 289

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{289 - 273}{\frac{100}{\sqrt{100}}}

Z = 1.6

Z = 1.6 has a p-value of 0.9452

X = 257

Z = \frac{X - \mu}{s}

Z = \frac{257 - 273}{\frac{100}{\sqrt{100}}}

Z = -1.6

Z = -1.6 has a p-value of 0.0648

0.9452 - 0.0648 =

0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

D) Which, if any of the sample sizes in part (a), (b), and (c) would you recommend to ensure at least a .95 probability that the same mean is withing $16 of the population mean?

None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

6 0
2 years ago
Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z ta
MrMuchimi

Answer:

The equation that best models this situation is :

b. \frac{x}{20}=\frac{x+400}{25}

Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 2,000 miles

Step-by-step explanation:

Given:

Time taken for Train W to complete a trip = 20 hours

Time taken for Train Z to complete a trip = 25 hours

The city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to.

both trains have same speeds and start from same location.

To find the distance in total each train travels.

Solution:

<em>Let length of the trip of Train W be </em>= x miles

Speed of Train W can be given as :

⇒ \frac{Distance}{Time}

⇒ \frac{x}{20}\ miles/h

<em>So, the length of the trip of Train Z will be</em> = (x+400) miles

Speed of Train Z can be given as :

⇒ \frac{Distance}{Time}

⇒ \frac{x+400}{25}\ miles/h

Since the speeds are same, so the equation to find x can be given as:

⇒ \frac{x}{20}=\frac{x+400}{25}

Solving for x

Multiplying both sides by 100 to remove fractions.

⇒ 100\times \frac{x}{20}=100\times \frac{x+400}{25}

⇒ 5x=4(x+400)

Using distribution.

⇒ 5x=4x+1600

Subtracting both sides by 4x

⇒ 5x-4x=4x-4x+1600

⇒ x=1600

Thus, Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 1600+400 = 2,000 miles

3 0
3 years ago
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