40 students prefer vanilla. To get this answer you need to multiply 200 times 0.2 because you are trying to find 20%
Answer:
See Below.
Step-by-step explanation:
We want to show that the function:
Increases for all values of <em>x</em>.
A function is increasing whenever its derivative is positive.
So, find the derivative of our function:
![\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5Be%5Ex%20-%20e%5E%7B-x%7D%5Cright%5D)
Differentiate:
Simplify:
Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>
Answer:
4/1000
Step-by-step explanation:
the value of 4 is 0.004 which in fraction form is 4/1000
First, make sure that all the variables are in one side. The first equation is gonna be x-y=3
Second, we are going to eliminate the y because it is much easier, but you can also eliminate the x
We have to add both equation because the y in the first equation is negative and in the second equation it’s positive.
We are left with 3x=9
Therefore, x=3
Last, substitute x= 3 in one of the equations
Y=6
P.O.I is (3,6)
