All you have to do is add all of the fractions up.
We are given with the following given
dV/dt = 35 m3/min
h = (3/2)D
What is asked is
dr/dt at t = 7 min
The volume of a cone is
V = (1/3)πr²h
From the given
h = (3/2)D
since D = 2r
h = 3r
Subsituting
V = πr³
At t = 7 min, the volume is
V = 35(7)
V = 245
and the radius is
245 = πr³
r = 4.27
Differentiating the volume
dV/dt = 3πr² dr/dt
From the given
dV/dt = 35
Subsituting
35 = 3πr² dr/dt
So,
dr/dt = 0.20 m/s
and
dh/dt = 0.60 m/s
The maximum number of miles she can drive is $111.388.
<h3>What is Unitary method?</h3>
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Step-by-step explanation:
The rental company charges $19.95
and, 18 cents for each mile driven.
So,
$40 - $19.95 = $20.05
Thus, the maximum number of miles she can drive
=$20.05 / by 0.18
= 111.388
Learn more about this concept here:
brainly.com/question/27826540
#SPJ1
Let
I1-------------> interest first day
I2-------------> interest second day
we know that
P0=$73000----------> initial amount
first day
I1=73000*(5%/100)*(1/365)-----------> I1=$10
P1=P0+I1------> $73000+$10-------- P1=$73010
second day
P1=$73010
I2=73010*(5%/100)*(1/365)-----------> I2=$10
P2=P1+I2------> $73010+$10-------- P2=$73020
the answer is $73020
Answer:
![v=364.5\ m^3](https://tex.z-dn.net/?f=v%3D364.5%5C%20m%5E3)
Step-by-step explanation:
<u>Volume Of A Regular Solid</u>
When a solid has a constant cross-section, the volume can be found by multiplying the area of the base by the height. The area of a trapezium is
![\displaystyle A_t=\frac{b_1+b_2}{2}h](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A_t%3D%5Cfrac%7Bb_1%2Bb_2%7D%7B2%7Dh)
where
and
are the lengths of the parallel sides and h the distance between them.
The figure shows a solid with a trapezoid as the constant cross-section and a height x. The volume of the solid is
![\displaystyle v=A_t\ x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3DA_t%5C%20x)
![\displaystyle v=\frac{b_1+b_2}{2}\ h\ x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7Bb_1%2Bb_2%7D%7B2%7D%5C%20h%5C%20x)
The image doesn't explicitly say if the length of 4.5 is the height of the trapezium or the length of that side. We'll assume the first, so our data is:
![\displaystyle b_1=7m,\ b_2=11m,\ h=4.5m,\ x=9m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20b_1%3D7m%2C%5C%20b_2%3D11m%2C%5C%20h%3D4.5m%2C%5C%20x%3D9m)
We now compute the volume
![\displaystyle v=\frac{7+11}{2}.(4.5)(9)=364.5](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7B7%2B11%7D%7B2%7D.%284.5%29%289%29%3D364.5)
![\boxed{\displaystyle v=364.5\ m^3}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdisplaystyle%20v%3D364.5%5C%20m%5E3%7D)