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____ [38]
3 years ago
13

If a figure is a square, in what other way or ways can you classify it? quadrilateral parallelogram rhombus all of the above are

accurate classifications for a square.
Mathematics
1 answer:
9966 [12]3 years ago
7 0
All of them are correct
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Susan has a collection of 65 nickels and dimes. If the number of nickels is four times the number of dimes, how many nickels and
NikAS [45]

Answer:

d = 13 and n = 52

Step-by-step explanation:

Number of dimes:  d

Number of nickels:  n

Then d + n = 65, and n = 4d

Substituting 4d for n in the first equation, we get:

d + 4d = 65, or 5d = 65.  Then d = 13 and n = 52

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3 years ago
2.67 +4.56 hjkfghjfvgbn
vfiekz [6]

Answer:

7.23

Step-by-step explanation:

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3 years ago
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Given that
Sveta_85 [38]

Answer:

x/20 = 5/x

x^2 = 100

x = 10

Let me know if this helps!

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3 years ago
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An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
4 years ago
Can anyone help me? I need to know this-
Alex17521 [72]

Answer:

x> -2

I hope this helps you...

3 0
3 years ago
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