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timama [110]
4 years ago
7

Find the percent of this number 55% of 900

Mathematics
2 answers:
Naddik [55]4 years ago
6 0
55\%\cdot900=\\
\frac{55}{100}\cdot900=\\
55\cdot9=\\
495
shutvik [7]4 years ago
4 0
You multiply .55 times 900. This equals 495. Hope I've helped you!
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Identify the slope intercept form
katen-ka-za [31]

Answer:

y=mx+b

Step-by-step explanation:

You would definitely want to memorize this important formula because you'll see this slope intercept form often in your Algebra I class, where m=slope and b=y-intercept.

5 0
4 years ago
Please help me if you can thank you.
Zielflug [23.3K]
Let the three consecutive odd numbers be x,x+2,x+4.
Given, their sum =219

Therefore, x+x+2+x+4=219
⇒3x+6=219
Subtract 6 from both the sides,
⇒3x+6−6=219−6

⇒3x=213
⇒x=71
The other numbers are x+2=71+2=73 and x+4=71+4=75.

Therefore, threee odd numbers are 71,73 and 75.
7 0
3 years ago
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Assuming only the lengths of the sides of a triangle are given, how can you determine if the triangle has a right angle?
saveliy_v [14]

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7 0
3 years ago
Find the 96th term of the arithmetic sequence 1, -12, -25, ...1,−12,−25,
IrinaK [193]

Answer:

a_9_6=-1,234

Step-by-step explanation:

we know that

The rule to calculate the a_n term in an arithmetic sequence is

a_n=a_1+d(n-1)

where

d is the common difference

a_1 is the first term

n is the number of terms

we have

1,-12,-25,...

Remember that In an Arithmetic Sequence the difference between one term and the next is a constant. and this constant is called the common difference

so

a_1=1\\a_2=-12\\a_3=-25

d=a_2-a_1=-12-1=-13

Find the 96th term of the arithmetic sequence

a_n=a_1+d(n-1)

we have

a_1=1\\d=-13\\n=96

substitute

a_9_6=1+(-13)(96-1)

a_9_6=1+(-13)(95)

a_9_6=1-1,235

a_9_6=-1,234

8 0
3 years ago
Hey good morning I need help ASAP thank you guys
mafiozo [28]

Answer:

B. x = 2.77

Step-by-step explanation:

3^x = 21

You first look for a base for 21 that is 3 to the power of something.

21 = 3^2.77

So 3^x = 2^2.77

They have the same base so

x= 2.77

8 0
3 years ago
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