7r²+9=1 quadratic equation.

1 answer:

7 0

7r²+9=1

the equation is contradictory, just to prove

7r² + 9 = 1

7r² + 9 -1 = 0

7r² + 8 = 0

We write the equation in the form of products of

7 * (r² + 8/7) = 0

the product is equal to 0 when one of the factors is zero

7≠0 ∨ (r² + 8/7) = 0
r² ≠ - 8/7
any number squared is not negative.

We proved that none of the factors is not equal to zero , so the right side of the equation is not equal to the left . The equation is contradictory

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Find the following when a = -1, b = 2, c = -1/4 (4b - 3)/(2a) -1

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We substitute the given into the equation
given: a=-1, b=2, c= $\frac{-1}{4}$
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= $\frac{4(2)-3}{2(-1)}$ -1
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to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
$\frac{5}{-2}$ =-2.5
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OR Common Denominator:
= $\frac{5}{-2}$ $\frac{-1}{1}$ × $\frac{-2}{-2}$ (denominator should be -2=common)
= $\frac{5}{-2}$ + $\frac{2}{-2}$
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What is the equation of a circle with center (-4,7) and a radius 6

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Answer:

( x +4)^2 + ( y-7)^2 = 36

Step-by-step explanation:

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( x-h)^2 + ( y-k)^2 = r^2

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( x- -4)^2 + ( y-7)^2 = 6^2

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