Answer:
Step-by-step explanation:
f(x - 3) is the horizontal shift 3 units right.
The B graph is displaying this translation, the graph A is also a horizontal shift of f(x) = x, but the shift is 3 units left.
The graphs C and D are vertical transformations and therefore incorrect.
Quadratic Equation:
What is the Vertex?
Vertex Form:
, where (h, k<span>) is the vertex of the parabola.
</span>
<span>Vertex is (6,25)
Axis of Symmetry?
This is just the h value so the AoS = 6
Total Distance? (I assume x-intercepts)
</span>
x-intercepts are (1,0) and (11,0) so in between them was the flight.
Domain and Range?
I'm not sure what domain and range are but I found a calc online for it and it says
Domain: <span><span>(<span><span>−∞</span>,∞</span>)</span>,<span>{<span>x|x∈R</span>}</span></span>Range: <span><span>(<span><span>−∞</span>,25</span>]</span>,<span>{<span>y|y≤25</span>}</span></span>
Answer:
Option B. 9.11
Step-by-step explanation:
To find the length of line AB, we must first of all calculate the value of θ as shown in the attached photo.
The value of θ can be obtained as follow:
θ + 39° + 120° = 180° (sum of angles in a triangle)
θ + 159° = 180°
Collect like terms
θ = 180° – 159°
θ = 21°
Thus, we can obtain the length of line AB by using sine rule as illustrated below:
b/Sine B = c/Sine C
b = 16
Angle B = 39°
Sine C = 21°
c =?
b/Sine B = c/Sine C
16/Sine 39° = c/Sine 21°
Cross multiply
c × Sine 39° = 16 × Sine 21°
Divide both side by Sine 39°
c = (16 × Sine 21°) / Sine 39°
c = 9.11
Therefore, the length of line AB is 9.11
Answer:
6.11km/hr
Step-by-step explanation:
Let the speed that Kelli swims be represented by Y
Speed of the river = 5km/hr
Distance = Speed × Time
Kelli swam upstream for some distance in one hour
Swimming upstream takes a negative sign, hence:
1 hour ×( Y - 5) = Distance
Distance = Y - 5
She then swam downstream the same river for the same distance in only 6 minutes
Downstream takes a positive sign
Converting 6 minutes to hour =
60 minutes = 1 hour
6 minutes =
Cross Multiply
6/60 = 1/10 hour
Hence, Distance =
1/10 × (Y + 5)
= Y/10 + 1/2
Equating both equations we have:
Y - 5 = Y/10 + 1/2
Collect like terms
Y - Y/10 = 5 + 1/2
9Y/10 = 5 1/2
9Y/ 10 = 11/2
Cross Multiply
9Y × 2 = 10 × 11
18Y = 110
Y = 110/18
Y = 6.1111111111 km/hr
Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.