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3 years ago

“15 subtracted from the product of a number squared and 4 is -59

Mathematics

1 answer:

BartSMP [9]3 years ago

4 0

Answer:

could you please be a little more explanatory? i don't understand what you're trying to say the equation is.

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3/2 x 4/3 x 5/4… x 2006/2005

Lady_Fox [76]

Answer:

1003

Step-by-step explanation:

The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.

The simplest form of a telescoping product $a_{k} \ = \ \displaystyle\frac{t_{k}}{t_{k+1}}$ , in which the products of <em>n</em> terms is

$a_{1} \ \times \ a_{2} \ \times \ a_{3} \ \times \ \cdots \times \ a_{n-1} \ \times \ a_{n} \ = \ \displaystyle\frac{t_{1}}{t_{2}} \ \times \ \displaystyle\frac{t_{2}}{t_{3}} \ \times \ \displaystyle\frac{t_{3}}{t_{4}} \ \times \ \cdots \ \times \ \displaystyle\frac{t_{n-1}}{t_{n}} \ \times \ \displaystyle\frac{t_{n}}{t_{n+1}} \\ \\ \-\hspace{5.55cm} = \ \displaystyle\frac{t_{1}}{t_{n+1}}.$ .

In this particular case, $t_{1} \ = \ 2$ , $t_{2} \ = \ 3$ , $t_{3} \ = \ 4$ , ..... , in which each term follows a recursive formula of $t_{n+1} \ = \ t_{n} \ + \ 1$ . Therefore,

$\displaystyle\frac{t_{2}}{t_{1}} \times \displaystyle\frac{t_{3}}{t_{2}} \times \displaystyle\frac{t_{4}}{t_{3}} \times \cdots \times \displaystyle\frac{t_{n}}{t_{n-1}} \times \displaystyle\frac{t_{n+1}}{t_{n}} \ = \ \displaystyle\frac{3}{2} \times \displaystyle\frac{4}{3} \times \displaystyle\frac{5}{4} \times \cdots \times \displaystyle\frac{2005}{2004} \times \displaystyle\frac{2006}{2005} \\ \\ \-\hspace{5.95cm} = \ \displaystyle\frac{2006}{2} \\ \\ \-\hspace{5.95cm} = 1003$

6 0

3 years ago

Need help now!!!!!!!

patriot [66]

Answer:

I got you.Use pemdas to solve this expression. First, evaluate the exponets, then multiply them together. Finally, divide that by 100.

8 0

4 years ago

Read 2 more answers

40/100= _ of_ Equal parts and the decimal _

Natasha_Volkova [10]

Not sure what the question is, but this is 4/10 or 0.4.

8 0

3 years ago

Helpppppppppppppppppppppppppp

Reil [10]

For this case we evaluate the function when x = 0
We then have to evaluate:
y = -2sinx - 1
y = -2sin (0) - 1
y = -1
Then, the intersection with the y-axis is -1 and the amplitude is 2.
Answer:
y = -2sinx - 1
option 2

3 0

3 years ago

Can someone pls help me with proving that (f)x^2-2|x| is increasing over [1;infinity] and decreasing over [0;1] then deduce that

dedylja [7]

Derivatives galore. Don't forget you might need to split the function because of the absolute value.

4 0

4 years ago

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