Answer:
The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the difference between population means is:
The information provided is as follows:
The critical value of <em>z</em> for 98% confidence level is,
Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:
Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
The first thing we must do for this case is to define variables.
We have then:
x = Tim's age
Now we write the equation:
x + 7 = 3 (x-19)
Answer:
Tim's age in 7 years will be three times what it was 19 years ago:
x + 7 = 3 (x-19)
Answer: C
Step-by-step explanation:
You can write each term into a fraction.
![\sqrt[5]{x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E4%7D)
becomes 
When you multiply 2 terms with the same base, you add the exponents.
is also the same as ![x\sqrt[5]{x^3}](https://tex.z-dn.net/?f=x%5Csqrt%5B5%5D%7Bx%5E3%7D)
You get this because ![\sqrt[5]{x^8} =\sqrt[5]{x*x*x*x*x*x*x*x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E8%7D%20%3D%5Csqrt%5B5%5D%7Bx%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%7D)
. When you pull out 5 os x, you are left with x³ on the inside.
1.03 Is approximately your answer
To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout
To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout
To find the total amount we add 2/12 and 3/12
3/12+2/12= 5/12
ANSWER:
5/12 of the fish she catches are trout
