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2 years ago

answer whether or not 2/3 of 3/4 of a pan of brownies is the same amount as 3/4 of 2/3 of a pan of brownies

Mathematics

1 answer:

Tom [10]2 years ago

3 0

Truthfulness check:

$\frac{2}{3} * \frac{3}{4} = \frac{3}{4} * \frac{2}{3}$
$\frac{6}{12} = \frac{6}{12} (TRUE)$

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Please help asap 20 pts

expeople1 [14]

B. If you were to solve for x, the values would be x=1.5275 and x=-1.5275.

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3 years ago

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What is the explicit rule for the arithmetic sequence shown in the graph ?

Elan Coil [88]

The answer is number 3, an=9.5+2(n-1)

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Stephen, Nick and Brian share £90 in a ratio 1:2:2. How much money does each person get?

malfutka [58]

Answer:

Stephen: £36

Nick: £36

Brian: £18

Step-by-step explanation:

2+2+1= 5

90/5= 18

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18x2=36

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Hope it helps

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3 years ago

Here is a triangular pyramid and its net.

galben [10]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

8 0

2 years ago

Hii! I need some help, would anyone mind helping me?

Kisachek [45]

Step-by-step explanation:

${x}^{2} - 14x - 25 {y}^{2} + 100y = 76$

Factor by grouping,

$( {x}^{2} - 14x) - (25 {y}^{2} - 100y) = 76$

Complete the square, with the x variables,

$( {x}^{2} - 14x + 49) - (25 {y}^{2} - 100y) = 125$

Factor out 25 for the y variables

$( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y) = 125$

Complete the square

$( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y + 4) = 25$

Simplify the perfect square trinomial

$(x - 7) {}^{2} - 25(y - 2) {}^{2} = 25$

Make the right side be 1 so divide everything by 25.

$\frac{(x - 7) {}^{2} }{25} - (y - 2) {}^{2} = 1$

Here our center is (7,2).

8 0

2 years ago