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Ostrovityanka [42]
3 years ago
12

Solve for R 3 r + 4 ---------- = 5 2 r = ?

Mathematics
2 answers:
lakkis [162]3 years ago
6 0
To find r, first write out the equation:
\frac{3r+4}{2} =5
Next, multiply both sides by 2:
3r+4=10
Now, subtract both sides by 4:
3r = 6
Divide both sides by 3:
r=2

The answer to this problem is r = 2. Hope this helps and have a phenomenal day!
madreJ [45]3 years ago
4 0
Multiple 2 on both sides- 3r+4=10
Subtract 4 on both, left with 3r=6.
6 divide 3=2
R=2
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Answer:

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ME = \frac{0.326-0.244}{2}=0.041

0.285 \pm 0.041

Step-by-step explanation:

For this case we have a confidence interval given as a percent:

24.4\% \leq p \leq 32.6\%

If we express this in terms of fraction we have this:

0.244 \leq p \leq 0.326

We know that the confidence interval for the true proportion is given by:

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And thats equivalent to:

\hat p \pm ME

We can estimate the estimated proportion like this:

\hat p = \frac{0.244+0.326}{2}=0.285

And the margin of error can be estimaed using the fact that the confidence interval is symmetrical

ME = \frac{0.326-0.244}{2}=0.041

And then the confidence interval in the form desired is:

0.285 \pm 0.041

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3 years ago
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Read 2 more answers
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Answer:

B. 45.23 cm

Step-by-step explanation:

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=\frac{1}{2}\times 3.14\times 17.6 +17.6

=\frac{1}{2}\times 55.264 +17.6

=27.632 +17.6

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Loss of $1.20

Step-by-step explanation:

The possible outcomes for this lottery and their probabilities are:

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- a 2 in 100 chance of winning $120

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- a 93 in 100 chance of losing $10

Therefore, the expected value of this lottery when buying one ticket is:

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