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Ostrovityanka [42]
3 years ago
12

Solve for R 3 r + 4 ---------- = 5 2 r = ?

Mathematics
2 answers:
lakkis [162]3 years ago
6 0
To find r, first write out the equation:
\frac{3r+4}{2} =5
Next, multiply both sides by 2:
3r+4=10
Now, subtract both sides by 4:
3r = 6
Divide both sides by 3:
r=2

The answer to this problem is r = 2. Hope this helps and have a phenomenal day!
madreJ [45]3 years ago
4 0
Multiple 2 on both sides- 3r+4=10
Subtract 4 on both, left with 3r=6.
6 divide 3=2
R=2
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The altitude of a helicopter increases 1000 feet every 4 minutes.
tatiyna

Answer:

1/250

Step-by-step explanation:

1000/4 simplifies to 1/250

All you had to do was simplify it

8 0
3 years ago
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Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply​
kykrilka [37]

\cos(2x)  =  \cos(x)

Solution (1)

2x = x + 2k\pi

2x - x = 2k\pi

x = 2k\pi

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

2x =  - x  + 2k\pi

2x + x = 2k\pi

3x = 2k\pi

x =  \frac{2k\pi}{3}

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

6 0
2 years ago
What is the smallest positive degree angle measure equivalent to sin^-1 (0.391)?
natta225 [31]

Given:

The value is:

\sin^{-1}(0.391)

To find:

The smallest positive degree angle measure equivalent to \sin^{-1}(0.391).

Solution:

We have,

\sin^{-1}(0.391)

Using the scientific calculator, we get

\sin^{-1}(0.391)=23.0167366398^\circ

\sin^{-1}(0.391)\approx 23^\circ

Therefore, the smallest positive degree angle measure equivalent to \sin^{-1}(0.391) is 23 degrees.

5 0
2 years ago
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The population of a small town in Ohio was 3,800 people in I. It has slowly been decreasing at a rate of 25% per year. What will
MrRa [10]

Answer:

676 assuming the population is 3800 in 2019. If it's a different year then change t.

Step-by-step explanation:

P(t) = P_{0} (1+r)^t \\\\P(6) = 3800(1-.25)^6 \\=P(6) = 3800(.75)^6\\=676


3 0
2 years ago
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
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