In the figure, ABCD is a trapezoid with legs AB and CD.
Join AC and BD.
For the triangle CAD, from the vertex C, draw an altitude CE and for the triangle ABD, from the vertex B, draw an altitude BF.
Clearly, CE = BF = h (say) --- (1)
Note that the base of the triangles CAD and ABD are the same and is AD.
It is given that ar(CAD) = 
.
Now, ar(ABD) = 
= 
from (1)
= ar(CAD)
= .
Hence, area of Δ ABD = ..
Answer:
1) Allosaurus - A dinosaur that lived 145 to 155 million years ago.
2) T. Rex- It us well represented.
3) Moon rock - it is found on earths moon.
4) Sedimentary rock - Made out of small particles.
5) The Parthenon Sculptures - 30% of surviving was brought to the U.K.
6) Slate - A metamorphic rock composed to clay.
7) Mudstone - Grain size is up to 0.063 millimeters.
8) Conglomerate - Is longer than 2 mm in diameter.
9) Stegosaures - The moving plant eater.
10) Triceratops - A plant eater.
11) Apatosaurus - The best known species.
12) Lydia coin - Is the most famous coin.
Answer:
First box: 15 * 10^10.
Second box: 300,000,000 meters per second.
Third box: 48 * 10^-13 meters.
Fourth box: 167 * 10^-29 meters.
Step-by-step explanation:
These should be correct! I put them in order from the top empty box to the bottom empty box!!!
Please mark brainliest if correct!!!
Answer:
Perimeter is irrational
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Step-by-step explanation:
<em>The attachment is missing but the question is still answerable</em>
Given
Required
Determine if the Perimeter is rational or not
First, we need to determine the sides of the square;
Substitute
Take Square root of both sides
The perimeter of a square is calculated as:
<em>Because the value of </em><em>perimeter </em><em>can't be gotten by dividing two integers, then </em><em>perimeter is irrational</em>
Answer:
BE = FC = 3 inches, EF = 2 inches
Step-by-step explanation:
The sum of angles A and D is 180°, so the sum of their half-angles is 90°. That is, half of A plus half of B add to 90°, so the bisector from B intersects AE at a right angle. Call that point of intersection X.
Then angle ABX = angle EBX, so triangle ABX is congruent to triangle EBX. Sides AB and BE are corresponding sides of congruent triangles.
The same argument applies to sides DC and CF.
Thus we have BE = CF = 3 inches, and EF is the left-over distance, 2 inches.
