Answer:
I think its linear so I dont know 100% but I think it's a sorry if I'm wrong
Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
Answer:
13ft
Step-by-step explanation:
Kindly find attached a rough draft of the situation.
Step one:
Given data
The length of the slide represents the
Hypotenuse of the situation on the rough sketch
Angle =33°
Required
The height of the ladder which is the adjacent of the rough sketch represented by x
Step two:
Applying SOH CAH TOA
Cos θ= adj/hyp
Cos 33=x/15
0.84=x/15
Cross multiplying
x=0.84*15
x=12.6
To the nearest foot the ladder is 13ft tall
Answer:
C. 22 M
Step-by-step explanation: