A bus with a vertical wind shield moves horizontally
1 answer:
Answer:
(3) 53°
Explanation:
We want to measure the angle that the rains form with the vertical wind shield, so we have to measure the angle relative to the vertical. This means that we can write the following equation
where
is the speed of the rain, which travels vertically
is the speed of the bus, which travels horizontally
Substituting, we find
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Answer:
E = 1.19 N/C
Explanation:
Let's first determine the length of the arc which can be given as:
L= Rθ
where:
L = length of the arc
R = radius of curvature
θ = angle in radius
L = (9.09×10⁻²m)(2.59)
L = (0.0909)(2.59)
L = 0.235431 m
Then, the magnitude of electric field that Q produces at the center of curvature can be calculated by using the formula:
Since
where;
L = length
Q = charge
λ = density of the charge;
then substituting for λ, we have :
substituting our given parameter; we have:
E = 1.1889 N/C
E = 1.19 N/C
∴ the magnitude of the electric field that Q produces at the center of curvature = 1.19 N/C