Complete Question
The maximum electric field strength in air is 4.0 MV/m. Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air
Answer:
The value is 
Explanation:
From the question we are told that
The electric field strength is 
The diameter is 
Generally the radius is mathematically represented as

=> 
=> 
Generally the cross-sectional area is mathematically represented as



Generally the maximum power that can be delivered is mathematically represented as

Here c is the speed of light with value 
is the permittivity of free space with value 


Answer:
Liquid
Explanation: It can't be gas because gases are all around us and we can still see light. For solids it can't even move through a solid. Ex: If you're in a solid dome made of rock you can't get any light through. Let me know if I'm right!
Answer:
b = 5.164 m is the minimum thickness of the dam
Explanation:
Given
SG = 5
h = 20 m
b = ?
w = 1 m
γw = 9800 N/m³
We can get the forces as follows
Fp = γw*(h/2)*(h*w)
⇒ Fp = (9800 N/m³)*(20 m/2)*(20 m*1 m) = 1.96*10⁶N
W = (SG*γw)*(h*b*w)
⇒ W = (5*9800 N/m³)*(20 m*b*1 m) = (9.8*10⁵N/m)*b
Then, we apply
∑M₀ = 0 (counterclockwise)
- Fp*(h/3) + W*(b/2) = 0
⇒ - 1.96*10⁶N*(20 m/3) + (9.8*10⁵N/m)*b*(b/2) = 0
- 13.066*10⁶N-m + (4.9*10⁵N/m)*b² = 0
⇒ b = 5.164 m is the minimum thickness of the dam
This was kinda hard thinking it might be that the new force is going to 4 times bigger than the original one.
<u>Explanation:</u>
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