Question

In kite WXYZ , m∠XWY=47° and m∠ZYW=18° .

Answer 1

The answer is 115 dont worry i took the test alr

Answer 2

Answer: $\angle WZY=115^{\circ}$

Explanation: Since, here WXYZ is a kite where $\angle XWY=47^{\circ}$ and $\angle ZYW=18^{\circ}$

Thus according to the property of a kite ,

Exactly one pair of opposite angles are equal and The main diagonal bisects a pair of opposite angles.

Therefore, In kite  WXYZ ,

$\angle WZY=\angle WXY$   -------(1)

And, WY is the angle bisector of  kite WXYZ.

So,  $\angle ZWX=2\angle XWY=2\times 47^{\circ}=94^{\circ}$ ( because WY bisects $\angle ZWX$ into two equal angles $\angle XWY$ and $\angle ZWY$)

⇒$\angle ZWX=94^{\circ}$ -----(2)

Similarly, $\angle XYZ=2\angle ZYW=2\times 18^{\circ}=36^{\circ}$

⇒$\angle XYZ=36^{\circ}$ -----(3)

Since, WXYZ is a kite ⇒$\angle WXY+\angle XYZ+\angle WZY+\angle ZWX=360^{\circ}$ -------(4)

Therefore,  From equation (1), (2), (3) and (4),

We get, $\angle WZY=115^{\circ}$