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qwelly [4]
3 years ago
9

The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe

et, the area will remain the same. Find the dimensions of the original rectangle.
Mathematics
1 answer:
bezimeni [28]3 years ago
7 0
Assign the following variables for the origina3l rectangle:
let w = width let w + 8 = length and the area would be w(w + 8) = w² + 8w

No for the second rectangle:
let (w + 4) = width and (w + 8 - 5) or (w + 3) = length
Area = length x width or (w + 4)(w + 3) = w² + 3w + 4w + 12 using the foil method to multiply to binomials. Simplified Area = w² + 7w + 12

Now our problem says that the two area will be equal to each other, which sets up the following equation:

w² + 8w = w² + 7w + 12 subtract w² from both sides
8w = 7w + 12 subtract 7w from both sides
w = 12 this is the width of our original rectangle
recall w + 8 = length, so length of the original rectangle would be 20
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