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stich3 [128]
3 years ago
12

In 2001 the mint indoor pool vault record was 20 and 1/6 the women’s record for the indoor pool vault was 15 and 5/12 FT what is

the combined height of the two records?
Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer:

35 and 7/12 feet is the combined height of the two records.

Step-by-step explanation:

Height of the indoor pool vault record for men = 20 and 1/6 ft =\frac{121}{6} ft

Height of indoor pool vault record for women = 15and 5/12 ft =\frac{185}{12} ft

The combined height of the two records :

\frac{121}{6} ft+\frac{185}{12} ft

\frac{121\times 2}{6\times 2} ft+\frac{185}{12} ft

\frac{242}{12} ft+\frac{185}{12} ft

\frac{242+185}{12} ft=\frac{427}{12}=35\frac{7}{12}

35 and 7/12 feet is the combined height of the two records.

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