Andrea is selling candles for a fundraiser. She spent $50 on supplies for making the candles. She plans to sell the

NEED HELP ASAP!! ILL GIVE BRAINLIEST IF YOU GET IT RIGHT!!

sdas [7]

Explanation:

*Based on what i know / understand*

Well one thing is that it is not E (the last choice because the mean is not the same as the median, they are different, the mean is 10.4 while the median is 13.4

And it can not be C or D because the mean is less than the median. So it is rather A or B.

But I think it is B.

Sorry if its wrong ;-;

6 0

3 years ago

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate off

GuDViN [60]

Correct question is;

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate offered to a buyer, the number of sets sold will increase by 210 per week

A) Find the demand function (price p as a function of units sold x).

p(x)=______

(B) How large a rebate should the company offer the buyer in order to maximize its revenue?

$=_____

Answer:

A) p(x) = (-1/10)x + 590

B) Rebate = $170

Step-by-step explanation:

A) We are told that p(x) is the demand function and x is the number of TV sets sold per week.

Now, since for each $21 rebate offered, the number of sets sold increases by 210 per week, it means that the slope here of this demand function is; m = -21/210 = -1/10

Now, he has been selling 1400 TV sets a week at $450 each. This means; p(1400) = $450

Thus, the demand function will be;

p(x) - 450 = (-1/10)(x - 1400)

Expanding the RHS;

p(x) - 450 = (-1/10)x + 140

Add 450 to both sides to get;

p(x) = (-1/10)x + 140 + 450

p(x) = (-1/10)x + 590

B) Formula for revenue is;

R = price × quantity sold

Our demand function is p = (-1/10)x + 590

Making x the subject, we have;

x = 5900 - 10p

x is quantity sold.

Thus,

R = p(5900 - 10p)

R = 5900p - 10p²

Maximum price will occur at dR/dP = 0

Thus;

dR/dP = 5900 - 20p

At dR/dP = 0,we have;

20p = 5900

p = 5900/20

p = $280

Thus, rebate = 450 - 280 = $170

6 0

3 years ago

S641591 is a hacker don’t trust em

horrorfan [7]

Answer:

welp ok

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The point-slope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1= 1/4(x-12). what is the stadard

Monica [59]

Answer:

x - 4y = 8

Step-by-step explanation:

Since the Point-Slope Formula is already given to you, convert it to Slope-Intercept Form, and you do that by doing this:

y - 1 = ¼(x - 12) >> y - 1 = ¼x - 3

y - 1 = ¼x - 3

+ 1 + 1

--------------

y = ¼x - 2 >> Slope-Intercept Form

After doing this, you are ready to convert to Standard Form, and you do that by doing this:

y = ¼x - 2

-¼x -¼x

-----------

-¼x + y = -2

Now unfortunately, we do not want fractions as our coefficients, so the way to eliminate the fraction is to multiply the equation by the Multiplicative Inverse of -¼, which is -4:

-4[-¼x + y = -2] >> x - 4y = 8 → New equation without fractions

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

6 0

3 years ago

In a recent study of statistics students, a random sample of students were asked to provide the number of hours per week they sp

Airida [17]

Answer:

$ME=\frac{Upper-Lower}{2}= \frac{8.15-6.55}{2}= 0.80$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (6.55,8.15). And we can estimate the margin of error with this formula since the confidence interval is symmetrical:

$ME=\frac{Upper-Lower}{2}= \frac{8.15-6.55}{2}= 0.80$

3 0

3 years ago