1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yKpoI14uk [10]
3 years ago
12

I am going 60 miles away and I am driving 40 miles per hour the whole way how long will it take me to get there

Mathematics
1 answer:
andrezito [222]3 years ago
8 0

if you are driving 40 miles per hour

1 hour = 40 miles


60-40 = 20 miles left

20/40 = 0.5

1+0.5 = 1.5 total hours

You might be interested in
Write a linear function for the data in each table
daser333 [38]

Answer:

19. y=5x+-1

20. y=-2.5x+4

Step-by-step explanation:

19: 9-4=5

-1+5=4 so m=5

b=-1

so y=5x+-1

20: -1-1.5=-2.5

4+-2.5=1.5

so m=-2.5

b=4

so y= -2.5x+4

Please mark me brainliest

4 0
3 years ago
1/8= 12 true or false
N76 [4]

Answer:

false

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Given rs || qp, what is the value of x?
myrzilka [38]

In the given figure,

Angle 108° + 12x = 180°

because they for pair of co- interior angles which are supplementary.

so,

  • 12x + 108\degree = 180\degree

  • 12x = 180\degree - 108\degree

  • 12x = 72\degree

  • x =  \dfrac{72\degree}{12}

  • x = 6\degree

hence , value of x = 6°

5 0
2 years ago
Read 2 more answers
Look at the picture!!
Contact [7]

Answer:

Shapes w/ at least one pair of parallel sides: a, d

No parallel sides: b, c

Shapes w/ at least one obtuse angle: a, c

have a good day. <3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blen
Slav-nsk [51]

Answer:

Median = 90.4

Q_1 = 88.6

Q_3 = 92.2

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

Smallest = 83.4

Highest = 100.3

Next, group each dataset base on common whole numbers.

So, we have:

83.4

84.3\ 84.3

85.3

86.7\ 86.7\ 86.7

87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9

88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9

89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9

90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9

91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\  91.6\ 91.6\ 91.8\ 91.8

92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7

93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7

94.2\ 94.2\ 94.4\ 94.7

96.1\ 96.5

98.8

100.3

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}

  \begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}

From the above plot,

n = 83

The median is calculated as:

Median = \frac{n+1}{2}th

Median = \frac{83+1}{2}th

Median = \frac{84}{2}th

Median = 42nd

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

Median = 90.4

The lower quartile (Q) is calculated as:

Q_1 = \frac{n+1}{4}th

Q_1 = \frac{83+1}{4}th

Q_1 = \frac{84}{4}th

Q_1 = 21st

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

Q_1 = 88.6

The upper quartile (Q3) is calculated as:

Q_3 = 3 * \frac{n+1}{4}th

Q_3 = 3 * \frac{83+1}{4}th

Q_3 = 3 * \frac{84}{4}th

Q_3 = 3 * 21th

Q_3 = 63rd

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

Q_3 = 92.2

8 0
3 years ago
Other questions:
  • Mr. jacobson asked her students write a word problem that describes the graph below.
    14·2 answers
  • Scot wants to buy a scooter that cost $129 this is$24 more than 3 times what He saved last month how much he did save last month
    13·2 answers
  • What is the radical form?
    5·1 answer
  • Determine the equation of the graph and select the correct answer below.
    13·1 answer
  • Un muchacho compra el mismo numero de lapices que de lapiceros por 90 soles.Cada laliz le cuesta 3 soles y cada lapicero 7 soles
    8·1 answer
  • Anyone know the answers??
    13·1 answer
  • Help on this this is the last one promise!!
    5·2 answers
  • A Reflection<br> B Translation <br> C Rotation<br> D Dilation<br><br> Please need help on this
    6·2 answers
  • Pls help me with this i will give brainliest if two ppl answer :)
    13·2 answers
  • Writing the equation of the line given slope and y-intercept
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!