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3 years ago

Is 0 a complex, pure imaginary, and a nonreal complex number?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

7 0

Answer:

Step-by-step explanation:

First, 0 doesn't have any i values, so 0 is not pure imaginary.

Also, 0 is indeed a real number, so it is not a "non-real complex number."

Therefore, the only option left is that 0 is a complex number, and 0 is indeed a complex number.

The answer is A.

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The area of a triangle is the product of the base of the triangle times the height of the triangle, divided by two.

trasher [3.6K]

Answer:

Step-by-step explanation:

Almost correct. I'd write this statement as follows:

"The area of a triangle is the product of the base and height of the triangle, divided by two."

or...

"The area of a triangle is half the product of the base and height."

3 0

2 years ago

3x + 5y = -19 5x - 2y = 16 solve for x and y

beks73 [17]

Step-by-step explanation:

2(3x + 5y = -19)

6x + 10y = -38

5 (5x -2y = 16)

25x - 10y = 80

19x = 42

but idk from there the rest doesn't work Soo if u can find the prob and tell me I'll fix it.

7 0

2 years ago

Help appreciated on question in image! Thanks:)

Verdich [7]

Answer:

$x=-1,\:x=-7,\:x=i,\:x=-i$

Step-by-step explanation:

Considering the equation

$x^4+8x^3+8x^2+8x+7=0$

Solving

$x^4+8x^3+8x^2+8x+7$

$\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=7,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

Solving

$\frac{x^4+8x^3+8x^2+8x+7}{x+1}$

$=x^3+7x^2+x+7$

Putting $\frac{x^4+8x^3+8x^2+8x+7}{x+1}$ = $x^3+7x^2+x+7$ in equation [A]

So,

$\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

$=\left(x+1\right)x^3+7x^2+x+7$

$x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)$

So,

Equation [A] becomes

$=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

So, the polynomial equation becomes

$\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$ $\mathrm{Solve\:}\:x+1=0:\quad x=-1$

$\mathrm{Solve\:}\:x+7=0:\quad x=-7$

$\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i$

$\mathrm{The\:solutions\:are}$

$x=-1,\:x=-7,\:x=i,\:x=-i$

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

#learnwithBrainly

5 0

2 years ago

Read 2 more answers

7th grade math. Solve. 9.4 = - t/3.5 t =

Naya [18.7K]

Answer:

t = - 32.9

Step-by-step explanation:

Step 1:

9.4 = - t ÷ 3.5 Equation

Step 2:

9.4 × 3.5 = - t Isolate the variable

Step 3:

32.9 = - t Multiply

Answer:

t = - 32.9

Hope This Helps :)

7 0

2 years ago

Which represents the number of lines of symmetry that are possessed by a regular n-gon?

anastassius [24]

Answer:

Option B. n

Step-by-step explanation:

we know that

A regular polygon is a convex polygon whose angles are all congruent.The number of lines of symmetry in a regular polygon is equal to the number of sides a regular polygon has.

therefore

the answer is option B. n

8 0

2 years ago