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svp [43]
3 years ago
9

a red ball and 4 white ball are in a box if two balls are drawn without replacement ,what is the probability of getting a red ba

ll on the first drawn and a white ball on the second​
Mathematics
1 answer:
BARSIC [14]3 years ago
3 0

The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

<u>Step-by-step explanation:</u>

  • There are 1 red ball and 4 white balls in a box.
  • The total number of balls in the box = 1 red + 4 white = 5 balls.

The two balls are drawn without replacement.

<u>Drawing the first ball :</u>

The first draw should be a red ball.

The probability to get a red ball = No.of red balls / Total balls in the box.

We know that, No. of red balls is 1 and total balls in the box is 5.

P(red ball) = 1/5

<u>Drawing the second ball :</u>

The second draw should be a white ball.

The probability to get white ball = No.of white balls / Total balls in the box.

We know that,

No. of white balls is 4.

The total balls in the box after the first draw will be 4 balls.

P(white ball) = 4/4

The probability of getting a red ball on the first drawn and a white ball on the second​ draw = P(red ball) × P(white ball)

⇒ (1/5) × (4/4)

⇒ 4/20

⇒ 1/5

Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

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denis23 [38]

Answer:

3.5 YARD

Step-by-step explanation:

3.5 x 3= 10.5x12= 126

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Find the 11th term of the geometric sequence 6, -18, 54
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In Inglis County me were 2,277 student athletes competing in spring sports in 2014. Thai was of the number which was of the numb
Anna35 [415]
2014⇒2277 athletes

2013⇒2070 athletes.
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7 0
3 years ago
Find the cost price when,<br>(a) Selling price = Rs 725 and 15% gain​
Debora [2.8K]

Step-by-step explanation:

Selling Price (SP) = Rs. 725

profit rate (P%) = 15 %

Now

Cost Price (CP)

=  \frac{sp \:  \times 100}{100 + p\%}  \\  =  \frac{725 \times 100}{100 + 15}   \\  =  \frac{72500}{115}  \\  = rs \: 630.42

4 0
3 years ago
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
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