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svp [43]
3 years ago
9

a red ball and 4 white ball are in a box if two balls are drawn without replacement ,what is the probability of getting a red ba

ll on the first drawn and a white ball on the second​
Mathematics
1 answer:
BARSIC [14]3 years ago
3 0

The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

<u>Step-by-step explanation:</u>

  • There are 1 red ball and 4 white balls in a box.
  • The total number of balls in the box = 1 red + 4 white = 5 balls.

The two balls are drawn without replacement.

<u>Drawing the first ball :</u>

The first draw should be a red ball.

The probability to get a red ball = No.of red balls / Total balls in the box.

We know that, No. of red balls is 1 and total balls in the box is 5.

P(red ball) = 1/5

<u>Drawing the second ball :</u>

The second draw should be a white ball.

The probability to get white ball = No.of white balls / Total balls in the box.

We know that,

No. of white balls is 4.

The total balls in the box after the first draw will be 4 balls.

P(white ball) = 4/4

The probability of getting a red ball on the first drawn and a white ball on the second​ draw = P(red ball) × P(white ball)

⇒ (1/5) × (4/4)

⇒ 4/20

⇒ 1/5

Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

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Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

1) The other root is also a real number, but a different number

2) Its a repeated root, so the other root is the same number.

The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.

Following are 3 possibilities for the roots of a quadratic equation:

  1. 2 Real and Distinct roots
  2. 2 Real and Equal roots
  3. 2 Complex roots
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2000 has three zeros and 10 has one, so you add another zero to 2000 so it makes it 20,000
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A. Lin is using the diagram to prove the statement, "If a parallelogram has one
BigorU [14]

The congruence of the angles and triangles are proven as follows;

a. The composition angles of FGH are alternate interior angles to the composition angles of angle AHEF

b. The three sides of triangle ∆EHG are congruent to the three sides of triangle ∆GFE, therefore, triangles ∆EHG and ∆GFE are congruent by SSS congruency rule

<h3>What are congruent triangles?</h3>

The lengths of the three sides of triangles that are congruent.

a. The shape of quadrilateral EFGH = A parallelogram

The measure of angle HEF = 90°

Angle HEF = 90°

Angle HEF = Angle HED + Angle DEF

Angle HED is congruent to angle FGD (Alternate interior angles theorem)

Angle HED = angle FGD

Angle DEF is congruent to angle DGH (Alternate interior angles theorem)

Angle DEF = angle DGH

Angle FGH = Angle FGD + Angle DGH

Angle FGH = Angle HED + Angle DEF (Substitution property)

Angle FGH = Angle HEF (Transitive property)

Angle FGH = Angle HEF = 90°

Therefore, the statement that will help prove angle FGH is also a right is that angle FGH is the sum of angles FGD and angle DGH which are alternate interior angles to angles HED and DEF which makes up angle HEF, which is a right angle.

b. The two-column method can be used to prove that triangle EHG and triangle GFE are congruent as follows;

Statement. Reason

EF is congruent to HG. Opposite sides of a parallelogram are congruent

EH is congruent FG Opposite sides of a parallelogram are congruent

EG is congruent to EG Reflexive property of congruency

∆EHG is cong. to ∆GFE SSS, Side-Side-Side, congruency rule

Learn more about the triangle congruency rules here:

brainly.com/question/15338506

#SPJ1

4 0
1 year ago
Please help asap, its due in 20min
mojhsa [17]

Answer:

The scalar factor is 4/3

Step-by-step explanation:

The bottom of triangle B is 16 units, the bottom of triangle A is 12 units. So to find the scalar factor you have to divide B by A:

6/12=4/3

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