Answer:
You Probably should’nt do that
Explanation:
The correct answer is Boolean logic.
Booleans are true or false statements.
An example of a while loop is:
while 1 < 5:
#do something.
The Boolean statement is 1 < 5 which evaluates to true because 1 is less than 5.
I hope this helps!
Answer:
def occurencesOfWords(words,freq):
frequency_dictionary={}
matched_frequency_words=[]
for i in range(len(words)):
counter=1
a=words[i].lower()
for j in range(len(words)):
if(i==j):
continue
b=words[j].lower()
if(a==b):
counter+=1
frequency_dictionary[words[i]]=counter
for key in frequency_dictionary:
if(frequency_dictionary[key]==freq):
matched_frequency_words.append(key)
return matched_frequency_words
if __name__=='__main__':
user_input=input()
freq=int(input())
words=user_input.split(" ");
required_words=occurencesOfWords(words,freq)
for s in required_words:
print(s)
Explanation:
- Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string
.
- matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
- Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
- Increment the counter variable, if two string are equal.
- Loop through the frequency_dictionary to get the matching frequency strings
.
- Finally test the program inside the main function.
Open Slide how Tab Then Set up Group and then Select Rehearse set each slide time according to your requirement
Answer:
probably the pincky finger I don't know I use what ever
