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just olya [345]
3 years ago
13

A carver begins work on the following block of granite that weighs 2700 g. What is the density of the granite?

Computers and Technology
1 answer:
bogdanovich [222]3 years ago
8 0

Given that,

Mass of the block, m = 2700 g

Let the dimensions of the block are 20 cm, 5 cm and 10 cm.

To find,

The density of the granite.

Solution,

Let d is the density of the granite. We know that the density of an object is equal to the mass per unit volume. So,

d = m/V

or

d=\dfrac{2700\ g}{20\ cm\times 5\ cm\times 10\ cm}\\\\d=2.7\ g/cm^3

So, the density of the block is 2.7 m/s².

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Given two Strings String s1 = "11223351638791377189728193"; String s2 = "983763978669976862724569282405742578"; and String varia
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Answer:

import java.math.BigInteger;  

public class Main {  

public static void main(String[] args)  {  

String s1 = "11223351638791377189728193";   String s2 = "983763978669976862724569282405742578";

BigInteger num1 = new BigInteger(s1);  

BigInteger num2 = new BigInteger(s2);  

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String s3 = product.toString(10);

System.out.println(s3);  

}  

}  

Explanation:

Because s1 and s2 contain large integers, the program need the biginteger module in other to compute the products of s1 and s2 when converted to integers.

This line initializes the two string variables s1 and s2

String s1 = "11223351638791377189728193";   String s2 = "983763978669976862724569282405742578";

The next two lines convert the two strings to BigInteger. This allows the program to multiply large integers

<em> BigInteger a = new BigInteger(s1);   </em>

<em>BigInteger b = new BigInteger(s2);  </em>

<em />

This computes the product of the two big integers

BigInteger product = num1.multiply(num2);  

This converts the product to String s3

String s3 = product.toString(10);

This prints s3

System.out.println(s3);  

}  

}  

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