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alexgriva [62]
3 years ago
15

I need help with question 16!

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0
Work out 9/25 of 100
To do this divide 100 by 25 = 4
Then multiply 4 by the numerator : 9*4 = 36
This means 36 people didn't like the book

So if there's 100 students altogether and 36 didn't like the book,
100-36 = 64

64 people liked the book
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I need help with number 1
Marianna [84]

Answer:

1a. 0< -4 false

1b. -3> or = -7 true

1c. 4<= -1/2 false

8 0
3 years ago
You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

So, the  distance travelled on the 7th day is 19.9 miles.

7 0
3 years ago
-5(-7,3) in y=mx+b form
kenny6666 [7]
Assuming -5 is m

y-3 = -5 (x + 7)
y - 3 = -5x - 35 
y = -5x - 33

hope this helps , give brainliest.
7 0
3 years ago
Evaluate the functions​
Anna11 [10]

Answer:

(btw the first question answer is -4, not 0)

10

Step-by-step explanation:

(btw the first question answer is -4, not 0)

So to solve the 2nd equation you substitute t with 30

so 30-2/3*30

30-20=10

6 0
3 years ago
You arrive in my class 45 seconds after leaving math which is 90 meters away
GenaCL600 [577]
If you are looking for the average speed, it is 2m/1 sec.
3 0
3 years ago
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