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VladimirAG [237]
3 years ago
7

Find the area of the triangle

Mathematics
1 answer:
Goshia [24]3 years ago
6 0

I wrote the steps down, hopefully you understand them and the answer is on the lower right corner.

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Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin
34kurt

Answer:

                \dfrac{1}{30}

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

1•1•4•3 = 12

The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}

7 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
5/6 of all the money in Salma's bank account is ₹55,000. how much money does Salma have in her bank account?
Vedmedyk [2.9K]

Answer:

₹66,000

Step-by-step explanation:

If 5/6 is 55,000 then just multiply 55,000 by the reciprocal  6/5 to get 66,000

8 0
2 years ago
Correct answers gets most brainiest!! :)
podryga [215]
Hello :)

Answer: x=11

Measure angel BAD= 122

Explanation:

To find X you have to make an equation

10x-49=5x+6

And then you solve for x

To find the angel measure of BAD, you have to add bac and cab to get bad

Bac= 10(11)-49 which equals 61

Cab= 5(11)+6=61

61+61= 122

Which is the measure of BAD

I hope this helps and have a wonderful rest of your night
6 0
2 years ago
at a restaurant the ratio of kids meal, how manys sold to adult meals sold was 9:2. if there were 81 kids meals sold, how many a
DedPeter [7]
9/2 = 81/a....9 kids meals to 2 adult meals = 81 kids meals to a adult meals
cross multiply
9a = 2(81)
9a = 162
a = 162/9
a = 18...so there were 18 adult meals
ratio is : 81/18 
6 0
3 years ago
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