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3 years ago

Which expression is equivalent to 1/27

Mathematics

1 answer:

blagie [28]3 years ago

6 0

Answer:

Step-by-step explanation:

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Y = -3x + 5? *<br> What’s the slope of the equation y =-3x+5

Crazy boy [7]

Answer:

The slope is -3

Step-by-step explanation:

The formula is y= mx + b

m = slope

b= y intercept

Therefore, the slope is -3

4 0

2 years ago

Please help me i need an answer

prohojiy [21]

Let the number be n
Part A- 2/3 + n = 2n+3
Part B- n= 2/3 -3
n= 2-9 / 3
n= -7/3 =-2.33

3 0

3 years ago

Read 2 more answers

Which expression means the sum of 5 and a number? A. g × 5 B. g – 5 C. g + 5 D. g ÷ 5

wel

For this case, the first thing you should do is define a variable.
We have then:
g: unknown number.
We now write the expression in algebraic form.
the sum of 5 and a number:
g + 5
Answer:
An expression that means the sum of 5 and a number is:
C. g + 5

5 0

3 years ago

Describe the process of rewriting the expression Please Help

Mazyrski [523]

Answer:

$x^{\frac{21}{4} }$

Step-by-step explanation:

Given expression is:

$(\sqrt[8]{x^7} )^{6}$

First we will use the rule:

$\sqrt[n]{x} = x^{\frac{1}{n} }$

So for the given expression:

$\sqrt[8]{x^{7}}=(x^{7} )^{\frac{1}{8} }$

We will use tha property of multiplication on powers:

$=x^{7*\frac{1}{8} }$

$= x^{\frac{7}{8} }$

Applying the outer exponent now

$(x^{\frac{7}{8} })^6$

$= x^{\frac{7}{8}*6 } \\= x^{\frac{42}{8} }\\= x^{\frac{21}{4} }$

8 0

2 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

3 years ago