R, h, g, s, and p are all constants, so that would be 8/11, or 72% of a chance of getting a consonant.
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0.123456789 not even joking thats the answer I did it on a calculator ♀️
Answer:
a=10, b=5, c=2, d=12
Step-by-step explanation:
Multiply each variable together
5*2=10
8*3=24
10
/24x
the coefficients (numbers) can each be divided by 2
5
/12x
subtract the "x" exponents together
5
/12
Answer:
Step-by-step explanation:
We can calculate this confidence interval using the population proportion calculation. To do this we must find p' and q'
Where p' = 14/100= 0.14 (no of left handed sample promotion)
q' = 1-p' = 1-0.14= 0.86
Since the requested confidence level is CL = 0.98, then α = 1 – CL = 1 – 0.98 = 0.02/2= 0.01, z (0.01) = 2.326
Using p' - z alpha √(p'q'/n) for the lower interval - 0.14-2.326√(0.14*0.86/100)
= -2.186√0.00325
= -2.186*0.057
= 12.46%
Using p' + z alpha √(p'q'/n)
0.14+2.326√(0.14*0.86/100)
= 0.466*0.057
= 26.5%
Thus we estimate with 98% confidence that between 12% and 27% of all Americans are left handed.
