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HACTEHA [7]
3 years ago
5

What is the least positive integer?

Mathematics
1 answer:
k0ka [10]3 years ago
3 0
-1? I'm guessing the least
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The measure of arc LK is?
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Because MK is a diameter, then angle L is a right angle. We already know that the measure of angle K is 50, so the measure of angle M has to be 40 because of the triangle angle-sum theorem. The rule for inscribed angles and the arcs they cut off is that the angle is half the measure of its intercepted arc or, likewise, the arc is twice the measure of the angle that cuts it off. Since arc LK is across from angle M and is cut off by angle M, then arc LK is twice the measure of angle M, and is 80. That's the same reason why angle L is 90; arc MK is a semi-circle, with a degree measure of 180, and angle L is half of that.

Arc LK = 80

5 0
3 years ago
In the diagram, AABC ~ ADEF. Find the value of x.
Andrew [12]

Answer:

B

Step-by-step explanation:

bdeehvdvjwjkwkwwjehheeh

If you dont know the anwser its always B

3 0
3 years ago
1 question geometry :) thanks if you help
Inessa05 [86]

Step-by-step explanation:

II will be the 90° clockwise rotation,

III will be the translation

IV will be the 180° rotation

V will be the 90° counter clockwise rotation

3 0
3 years ago
The sum of 4 times a number and -2 is equal to the sum of 5 times the number and -2. Find the number
MArishka [77]
4n(-2)=(5)(-2)
-8n=-10
—— —-
-8 -8

n= 5/4
n= 1 1/4

So the final answer is n= 1.25
6 0
3 years ago
8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.
PIT_PIT [208]

Answer:

a. 720

b. 0.3

Step-by-step explanation:

a.

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

b.

There are three cases that satisfy this condition

  1. first ball picked is 5, the others are not
  2. first ball is not 5, second is 5, third is not
  3. first and second ball is not five, third ball is 5

Each probabilities are:

  1. \frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}
  2. \frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}
  3. \frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}

Thus, one of the balls selected is the number 5 is then \frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}

5 0
3 years ago
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