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IRINA_888 [86]
3 years ago
15

A quarter weighs about 0.025 pound.what is this weight written in scientific notation

Mathematics
1 answer:
Mkey [24]3 years ago
8 0

       0.025   =   2.5 x 10⁻²

Regrdez, SVP.
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Use the given graph to determine the limit, if it exists. (4 points)
skelet666 [1.2K]
<h3>Answer:  3</h3>

Explanation:

Refer to the graph below. It should be similar to what your teacher gave you, based off the description.

Since we're approaching 3 from the right side, this means we'll be working with the horizontal line portion. We could start at something like x = 3.2 and move closer to 3 by getting to x = 3.1 then x = 3.01 then x = 3.001 and so on. We never actually get to 3 itself.

As x gets closer to 3 from this direction, the y values are approaching 3 since every point on this horizontal line has the same y coordinate. Technically the y value is already at 3, but it's the same idea.

In terms of notation, we can write \displaystyle \lim_{x\to3^{+}}f(x) = 3

The portion x \to 3^{+} means we're approaching 3 from the positive side, aka the right hand side on the number line.

8 0
2 years ago
Simplify without the absolute value |x+3| ; if x&gt;2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
Harper sold a $350,000 home. She earned 3% commission. How much did she make off the sale of the home?
Luden [163]

Answer:

10500 dollars

Step-by-step explanation:

350,000 * .03 = 10500

4 0
3 years ago
HELP ME PLEASE IVE BEEN STRUGGLING WITH THIS FOR SO LONG
Ber [7]

Answer:

<h2>m∠ACE = 90°</h2>

Step-by-step explanation:

Figure Interpretation:

m∠CBA + m∠CDE = 180

m∠BCA = (180-m∠CBA)/2

m∠DCE = (180-m∠CDE)/2

=======================

Then

m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2

                                = [360-(m∠CBA+m∠CDE)]/2

                                = [360 - 180]/2

                                = 90

finally,

m∠ACE= 180 - (m∠BCA + m∠DCE)

             = 180 - 90

             = 90

8 0
2 years ago
The graph below shows the heights and arm spans of students in a classroom. Height and Arm Span of Students Based on the graph,
xxMikexx [17]

The best prediction of the height of a student with an arm span of 143 cm is 143 cm

Step-by-step explanation:

The missing graph is attached

The graph below shows the heights and arm spans of students in

a classroom

  • The x-axis represents the height in cm
  • The y-axis represents the arm span in cm

We need to find the height of a student with an arm span of 143 cm

∵ The graph does not contain the value of the given arm span

∴ We will use the line best fit (sold line in the attached graph) to find

   the best predication of the height

∵ The line passes through points (150 , 150) and (160 , 160)

- The x-coordinates are equal the y-coordinate

∴ The equation of the line is y = x

∵ The arm span of a student is 143 cm

∵ y represents the arm span of a student

∴ y = 143

- Substitute the value of y in the equation of the line best fit

∵ y = x

∴ 143 = x

∵ x represents the height of a student

∴ The height of the student is 143 cm

The best prediction of the height of a student with an arm span of 143 cm is 143 cm

Learn more:

You can learn more about line best fit in brainly.com/question/8955867

#LearnwithBrainly

3 0
3 years ago
Read 2 more answers
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