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2 answers:
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Answer:
a) 61.2, b) 38.4 and c) 4.98
Step-by-step explanation:
Given:
The mean width of 12 I-Pads is 5.1 inches.
The mean width of 8 Kindles is 4.8 inches.
Question asked:
a. What is the total width of the I-Pads?
b. What is the total width of the Kindles?
c. What is the mean width of the 12 I-Pads and 8 Kindles?
Solution:
<u>As we know:</u>
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a) Thus, the total width of the I-Pads are 61.2 inches.
b) Thus, total width of the Kindles are 38.4 inches.
Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches
Combined number of observations = 12 + 8 =20
Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles Combined number of observations
Combined mean of width of the 12 I-Pads and 8 Kindles =
c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.
Answer:
Step-by-step explanation:
The center is halfway between vertices, at (4, -6).
It is also halfway between foci.
:::::
The vertices are vertically aligned, so the parabola is vertical.
General equation for a vertical ellipse:
(y-k)²/a² + (x-h)²/b² = 1
with
center (h,k)
vertices (h,k±a)
co-vertices (h±b,k)
foci (h,k±c), c² = a²-b²
Apply your data and solve for h, k, a, and b.
center (h,k) = (4, -6)
h = 4
k = -6
vertices (4,-6±a) = (4,-6±9)
a = 9
foci (4,-6±c) = (4,-6±5√2)
b² = a² - c² = 9² - (5√2)² = 31
b = √31
The equation becomes
(y+6)²/81 + (x-4)²/31 = 1
:::::
length of major axis = 2a = 18
length of minor axis = 2b = 2√31
