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Sidana [21]
3 years ago
11

From a sample with n=32, the mean duration of a geyser's eruption is 3.81 minutes and the standard deviation is 1.07 minutes. Us

ing Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.67 and 5.95 minutes.
Mathematics
1 answer:
Damm [24]3 years ago
5 0
Notice that

1.67=3.81-2\times1.07
5.95=3.81+2\times1.07

This means you are looking for

\mathbb P(1.67

Chebyshev's theorem states that for any constant k>0,

\mathbb P(|X-\mu|

which means

\mathbb P(1.67

In other words, at least 75% of the geysers will have eruptions lasting between 1.67 and 5.95 minutes. Out of 32 geysers, then, one can expect at least 24 of them to have eruptions with between these durations.
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54 gallons

Step-by-step explanation:

  • 12 × 4.5 =54 gallons

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A.63<br> B.54<br> C.99<br> D.126
Neporo4naja [7]

Answer:

C

Step-by-step explanation:

Area = (8 + 14) x 1/2 x 9

Area = 22 x 1/2 x 9

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<em>Hope that helps!</em>

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Proof David Berkowitz is a psychopath <br><br> 25 points + marked brainiest!
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Step-by-step explanation:

4 0
3 years ago
6a-2(4a-5)=40<br>How do I solve it​
Elza [17]

Answer:

Distribute, then combine like terms, subtract 10 from both sides of the equation, simplify, divide both sides of the equation by the same term, and simplify to get your solution.

Step-by-step explanation:

1.) Distribute

6−2(4−5)=40

6−8+10=40

2.) Combine like terms

6a-8a+10=40

-2a+10=40

3.) Subtract 10 from both sides of the equation

-2a+10=40

-2a+10-10=40-10

4.) Simplify

subtract the numbers

-2a+10-10=40-10

-2a=40-10

subtract the numbers

-2a=40-10

-2a=30

-2a=30

5.) Divide both sides of the equation by the same term

-2a=30

\frac{-2a}{-2} =\frac{30}{-2}

6.) Simplify

cancel terms that are in both the numerator or denominator

\frac{-2a}{-2} =\frac{30}{-2}

a=\frac{30}{-2}

Divide the numbers

a=\frac{30}{-2}

a=-15

a=-15

7.) Solution

a=-15

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3 years ago
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