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Sidana [21]
3 years ago
11

From a sample with n=32, the mean duration of a geyser's eruption is 3.81 minutes and the standard deviation is 1.07 minutes. Us

ing Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.67 and 5.95 minutes.
Mathematics
1 answer:
Damm [24]3 years ago
5 0
Notice that

1.67=3.81-2\times1.07
5.95=3.81+2\times1.07

This means you are looking for

\mathbb P(1.67

Chebyshev's theorem states that for any constant k>0,

\mathbb P(|X-\mu|

which means

\mathbb P(1.67

In other words, at least 75% of the geysers will have eruptions lasting between 1.67 and 5.95 minutes. Out of 32 geysers, then, one can expect at least 24 of them to have eruptions with between these durations.
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Y= -0.25x + 4.7<br> Y=4.9x - 1.64
Andreas93 [3]

Answer:

The answer would be (1.23, 4.39)

Step-by-step explanation:

Because they are both equal to y, we can set the equations equal to each other and then solve.

4.9x - 1.64 = -0.25x + 4.7

5.15x - 1.64 = 4.7

5.15x = 6.34

x = 1.23

Now that we have the value for x, we can plug into either equation and find y.

y = -0.25x + 4.7

y = -0.25(1.23) + 4.7

y = -.31 + 4.7

y = 4.39

3 0
4 years ago
340 pages; 20% decrease=? (With work plz)
pishuonlain [190]
340 × .2 = 68

68 page decrease

340 - 68 = 272

272 pages left
4 0
3 years ago
Find the average rate of change of the function over the given interval.
Minchanka [31]

Answer:

Average rate of change = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

Step-by-step explanation:

The average rate of change of the function

F(t) = 2t^2 - 1 ,  [ 5,5.1 ]

solution

\frac{f(5.1)-f(5)}{5.1 - 5} = \frac{2*(5.1)^2-1-(2*5^2-1)}{0.1}   = [ 2 ( 26.01 - 25 ) / 0.1 ]

= 2.02 / 0.1 = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

6 0
4 years ago
The vertices of a triangle are P(-1, 3), Q(2, -1), and R(5, 3).
Morgarella [4.7K]
Ok so to find which sides are congruent we need to know their lengths.

To find the length we need the distance formula between two point ->

√(X2-X1)∧2 +(Y2-Y1)∧2

Ok lets find the first side PQ

P(-1,3) Q(2,-1)
   X1 Y1  X2 Y2

√(2-(-1)∧2 + (-1-3)∧2 = 5

Now PR

P (-1,3) R (5,3)
    X1 Y1  X2 Y2

√(5-(-1))∧2 + (3-3)∧2) = 6

Now the last side QR

Q (2, -1) R (5,3)
   X1  Y1    X2 Y2

√(5-2)∧2 + (3-(-1))∧2 = 5

From the above work we see that PQ and QR are congruent becuase they are equal PQ=QR

Also the opposite angles of these sides are congruent. Hope this helps :).

8 0
4 years ago
Read 2 more answers
15. 12, 8, 14, 7, 16, 6, 18, .......,<br>b. 6, 20<br>a. 5, 18<br>d.6,21<br>C. 5, 20​
babymother [125]

Answer:

What is the question. Please rewrite the question.

8 0
3 years ago
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