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Sidana [21]
2 years ago
11

From a sample with n=32, the mean duration of a geyser's eruption is 3.81 minutes and the standard deviation is 1.07 minutes. Us

ing Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.67 and 5.95 minutes.
Mathematics
1 answer:
Damm [24]2 years ago
5 0
Notice that

1.67=3.81-2\times1.07
5.95=3.81+2\times1.07

This means you are looking for

\mathbb P(1.67

Chebyshev's theorem states that for any constant k>0,

\mathbb P(|X-\mu|

which means

\mathbb P(1.67

In other words, at least 75% of the geysers will have eruptions lasting between 1.67 and 5.95 minutes. Out of 32 geysers, then, one can expect at least 24 of them to have eruptions with between these durations.
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blondinia [14]

Answer:

b- 13 weeks

Step-by-step explanation:

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3 0
2 years ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

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we know that sum of all angles is 180

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we can plug values

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we can use law of sines

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BC=\frac{8}{sin(45)} \times sin(60)

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\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

now, we can plug values

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

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p=AB+BC+AC

we can plug values

p=10.928+8+9.798

p=28.726

Area:

we can use formula

A=\frac{1}{2}AB \times AC \times sin(A)

now, we can plug values

A=\frac{1}{2}8 \times 10.928 \times sin(60)

A=37.85570...............Answer

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sleet_krkn [62]
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Answer: 6

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