G(x)=3x-2;find g(7)
2 answers:
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Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:
We know that:
Then our integral is:
The right side is equal to:
The bounded area is 5 + 5/6 square units.
Answer:
<h2>sin(01) = -32.70/13</h2>Step-by-step explanation:
Given cos(01) = -30/13 where angle 01 is located in quadrant III. In the third quadrant, both cos and sin are negative. only tan is positive.
To calculate sin(01), we will apply the trigonometry expression as shown below;
cos(01) = -30/13
According to SOH CAH TOA;
cos(01) = adjacent/hypotenuse = -30/13
sin(01) = opposite/ hypotenuse
To get the hypotenuse, we will use the pythagoras theorem
sin(01) = 32.70/13
Since sin is also negaitve in the third quadrant, the value of
sin(01) = -32.70/13