PART 1If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.
For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²
I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.
PART 2If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.
For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3
I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.
SUMMARY
f(x+1/3) ⇒⇒ <span>f(x) is translated 1/3 units left.
f(x) + 1/3 </span>⇒⇒ <span>f(x) is translated 1/3 units up.</span>
![Vertex: \ (2,3)](https://tex.z-dn.net/?f=Vertex%3A%20%5C%20%282%2C3%29)
<h2>
Explanation:</h2>
The vertex form of the equation of a parabola is given by the following form:
![f(x)=a(x-h)^2+k \\ \\ Where: \\ \\ a:Leading \ Coefficient \\ \\ (h,k):Vertex \ of \ the \ parabola](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-h%29%5E2%2Bk%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20a%3ALeading%20%5C%20Coefficient%20%5C%5C%20%5C%5C%20%28h%2Ck%29%3AVertex%20%5C%20of%20%5C%20the%20%5C%20parabola)
In this exercise, we have the following equation:
![y=-(x-2)^2+3](https://tex.z-dn.net/?f=y%3D-%28x-2%29%5E2%2B3)
From here, we can conclude that:
![Leading \ coefficient: \ -1 \\ \\ Vertex: \ (2,3)](https://tex.z-dn.net/?f=Leading%20%5C%20coefficient%3A%20%5C%20-1%20%5C%5C%20%5C%5C%20Vertex%3A%20%5C%20%282%2C3%29)
Since the leading coefficient is less than zero, the parabola open downward. So, the graph is shown below and the vertex has been indicated.
<h2>Learn more:</h2>
Finding leading coefficient: brainly.com/question/1469367
#LearnWithBrainly
Answer:
the first one
Step-by-step explanation:
Answer:
D)- Less than 1 Mile
Step-by-step explanation: as current= 1 1/2 Miles = 3/2 Miles
Total plans= 2 1/3= 7/3 Miles
Difference= (7/3)-(3-2)
= 5/6 Miles