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GrogVix [38]
4 years ago
15

The area of circle K when c=24x^2 pi

Mathematics
1 answer:
Gala2k [10]4 years ago
6 0

Answer:\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }

Step-by-step explanation:

c=24x^2 pi

Switch sides:

24x^2\pi =Kc

divide both sides by 24\pi

\frac{24x^2\pi }{24\pi }=\frac{Kc}{24\pi }

simplify:

x^2=\frac{Kc}{24\pi }

x^2=\frac{Kc}{24\pi }x=\sqrt{\frac{Kc}{24\pi }},\:x=-\sqrt{\frac{Kc}{24\pi }}

answer:x=\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }

i hope it's help!

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