Question

The area of circle K when c=24x^2 pi

Answer 1

Answer:$\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }$

Step-by-step explanation:

$c=24x^2 pi$

Switch sides:

$24x^2\pi =Kc$

divide both sides by $24\pi$

$\frac{24x^2\pi }{24\pi }=\frac{Kc}{24\pi }$

simplify:

$x^2=\frac{Kc}{24\pi }$

$x^2=\frac{Kc}{24\pi }$$x=\sqrt{\frac{Kc}{24\pi }},\:x=-\sqrt{\frac{Kc}{24\pi }}$

answer:$x=\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }$

i hope it's help!