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dybincka [34]
4 years ago
10

The scale from a map to actual distance is 2.5 cm to 620 mi. The distance on the map between Chicago and Boston is about 3.5 cm.

What is the approximate distance, in miles, between Chicago and Boston? Show your work. Please help me
Mathematics
1 answer:
swat324 years ago
4 0

Answer: 868 miles

Step-by-step explanation:

Given: The scale from a map to actual distance is 2.5 cm to 620 miles.

i.e. 1 cm on map  = \dfrac{620}{2.5}\text{ miles}=248 \text{ miles}

If the distance on the map between Chicago and Boston is about 3.5 cm.

Then, the actual distance between them =  3.5\times 248 \text{ miles}=868 \text{ miles}

Hence, the approximate distance between Chicago and Boston = 868 miles.

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The area of a rectangular playground enclosure at francis lewis hw is 500 square meters. the lenght of the playground is 5 meter
Alex Ar [27]
A=L*W
L=W+5
A=(W+5)W
500=W²+5W
W²+5W-500=0

W=(-5+/-√(25+4*500))/2=(-5+/-√2025)/2=(-5+/-45)/2
we are going to take only positive value, so W=(-5+45)/2=20
L=W+5=20+5=25
W=20,
L=25

7 0
4 years ago
What is the slope of the line passing through the points (2, 5) and (-1, -4)? show your work
Sati [7]

Answer:

We can solve this question using the slope equation which is y2-y1/x2-x1

If you use that formula and sub in the coordinates

-4 - 5 / -1-2

-9/-3

= 3

The slope should be 3/1

5 0
3 years ago
Read 2 more answers
Un terreno cuadrado tiene una superficie de 900 metros cuadrados. ¿Cuántos metros lineales de alambre se necesitan para cercarlo
sveta [45]

Respuesta:

120 metros

Explicación paso a paso:

Dado que:

Área del lote cuadrado = 900 m²

Área, A de cuadrado = s²

Donde, s = longitud del lado

s² = 900

Toma el cuadrado de ambos lados

s = raíz cuadrada (900)

s = 30

Se requiere metro lineal de alambre para cercar, el lote será el perímetro del lote cuadrado;

El perímetro del lote cuadrado = 4s

Por eso,

Perímetro del lote cuadrado = 4 * 30

Perímetro del lote cuadrado = 120 m

3 0
3 years ago
Find the axis of symmetry for this parabola y=-5x^2-10x-15 write it as an equation
Ksju [112]
Axis of symmetry is the x value of the vertex

the x value of the vertex, in form
y=ax^2+bx+c is -b/(2a)

so
y=-5x^2-10x-15
a=-5
b=-10

x value of vertex is -(-10)/(2*-5)=10/-10=-1
x=-1 is axis of symmetry
6 0
4 years ago
Read 2 more answers
The sum of the first 10 terms of an AP is four times the sum of the first 5 terms then the ratio of the first term to the common
Mashcka [7]

Answer:

The ratio of the first term to the common difference is 1 : 2

Step-by-step explanation:

The rule of the sum of the AP is

S_{n}=\frac{n}{2}[2a+(n-1)d] , where

a is the first number

d is the common difference

n is the position of the number

∵ S_{10} = 4 × S_{5} ⇒ (1)

→ Find S_{10}  and S_{5}

∵ In S_{10} n = 10

∴ S_{10}=\frac{10}{2}[2a+(10-1)d]

∴ S_{10}=5[2a+9d]

∴ S_{10} = 10a + 45d ⇒ (2)

∵ In S_{5} n = 5

∴ S_{5}=\frac{5}{2}[2a+(5-1)d]

∴ S_{5}=2.5[2a+4d]

∴ S_{5} = 5a + 10d ⇒ (3)

→ Substitute (2) and (3) in (1)

∵ 10a + 45d = 4[5a + 10d]

∴ 10a +45d = 20a + 40d

→ Subtract 40d from both sides

∴ 10a + 45d - 40d = 20a + 40d - 40d

∴ 10a + 5d = 20a

→ Subtract 10a from both sides

∴ 10a - 10a + 5d = 20a - 10a

∴ 5d = 10a

→ Divide both sides by 5

∴ d = 2a

→ That means d is twice a or a is half d

∴ a : d = 1 : 2

The ratio of the first term to the common difference is 1 : 2

3 0
3 years ago
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