To evaluate the <span>probability that in a randomly selected hour the number of watches produced is greater than 500 we proceed as follows:
z=(x-</span>μ<span>)/</span>σ
where:
x=500
μ=500
σ=100
thus
z=(500-500)/200=0
Thus:
P(x>500)=1-P(x<500)=1-P(z<0)=1-0.5=0.5
Answer: 0.5~50%
Answer:
3/4 ÷ 1/2
Step-by-step explanation:
Since p=24 and to get p you do 3w+3w+w+w which equals 8w=24 and 24/8 is 3 so your answer is 3
Total money Marcus has = $28
Money spent to buy a notebook = $3.75
Money left now = 
Money needed to be saved = $11.25
So, the amount of money Marcus can spend = 
Cost of a packet of chips = $1.30
The inequality to determine the maximum number of chips he can buy is:
Let the number of chips Marcus can buy = x
As he cannot spend more than $13 to buy chips so equation becomes:

Solving this we get

Hence, Marcus can buy a maximum of 10 packs of chips and save $11.25
Answer: It is B
Step-by-step explanation:
Just took the test