A rectangle has a width of 2.5. When the length of this rectangle is decreased by 5 inches, the new area of the rectangle is 17.
1 answer:
<h3><u>Part A: An equation to represent this situation, where x represents the original length of the rectangle is:</u></h3>
<em><u>Solution:</u></em>
Given that,
A rectangle has a width of 2.5
Therefore,
width = 2.5 inches
Let "x" be the original length of the rectangle
When the length of this rectangle is decreased by 5 inches
Therefore,
New length = x - 5
The new area of the rectangle is 17.5 square inches
Therefore,
<em><u>The area of rectangle is given as:</u></em>
Thus original length of the rectangle is 12 inches
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Answer:
Tamara should expect the sum of the two cubes to be equal to 5 20 times.
Step-by-step explanation:
The sample space of rolling a number cube are:
S = {1, 2, 3, 4, 5, 6}
If two such cubes are rolled together, then the sum of the two cubes will be 5 for the combinations below:
S₁ = {(1, 4), (2, 3), (3, 2) and (4, 1)}
The total number of outcomes will be, <em>N</em> = 36.
Compute the probability that the sum of rolling two numbered cubes as follows:
Let <em>X</em> = number of time the sum of the two numbers on two cubes is 5.
Two numbered cubes are rolled <em>n</em> = 180 times.
The event of getting a sum of 5 in independent of the other results.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 180 and <em>p</em> = .
The expected value of <em>X</em> is:
Compute the expected number of times Tamara expects the sum of the two cubes to be equal to 5 as follow:
Thus, Tamara should expect the sum of the two cubes to be equal to 5 20 times.